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madreJ [45]
3 years ago
15

The relationship between angular acceleration α and torque τ is given by blank, where I is the moment of inertia., where I is th

e moment of inertia.
Physics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

\tau=I\times \alpha

Explanation:

The relationship between angular acceleration α and torque τ is given by :

\tau=I\times \alpha

Here,

I is the moment of inertia. It depends on the mass and the distance from the axis of rotation.

\alpha is the angular acceleration

Hence, this is the required solution.

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Choose the items that help to fully describe voltage.
Zina [86]

Answer:

the easy way to describe this is to use a light as an example.

Explanation:

Voltage is pretty much the loop used to help use a lightbulb to emit light. Without voltage, we would be unable to use lightbulbs. This applies to much more than a lightbulb, but it's the easiest way to describe how voltage works.

8 0
2 years ago
A 10-ohm resistor has a constant current. If 1200 C of charge flow through it in 4 minutes what
Amanda [17]

Answer:

B 5.0 A .

Explanation:

Hello.

In this case, since we know the charge (1200 C), time (4 min =240 s) and resistance (10Ω) which is actually not needed here, we compute the current as follows:

I=\frac{Q}{t}

Then, for the given data, we obtain:

I=\frac{1200C}{4min}*\frac{1min}{60s}\\\\I=5A

Therefore, answer is B 5.0 A .

Best regards!

4 0
3 years ago
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
labwork [276]

Answer:

9.4 m/s

Explanation:

According to the work-energy theorem, the work done by external forces on a system is equal to the change in kinetic energy of the system.

Therefore we can write:

W=K_f -K_i

where in this case:

W = -36,733 J is the work done by the parachute (negative because it is opposite to the motion)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving,

K_f = K_i + W=66,120+(-36,733)=29387 J

The final kinetic energy of the car can be written as

K_f = \frac{1}{2}mv^2

where

m = 661 kg is its mass

v is its final speed

Solving for v,

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

4 0
4 years ago
At the beach in San Francisco (0 meters) the pressure of the atmosphere is 101.325 kPa
Korvikt [17]

Answer:

P = -\frac{17978}{1609344}(h)+101.325

Explanation:

Given

h = height

P = Pressure

(h_1,P_1) = (0,101.325)

(h_2,P_2) = (1609.344 ,83.437 )

Required

Determine the linear equation for P in terms of h

First, we calculate the slope/rate (m);

The following formula is used:

m = \frac{P_2 - P_1}{h_2 - h_1}

Substitute values for P's and h's

m = \frac{83.347 - 101.325}{1609.344- 0}

m = \frac{-17.978}{1609.344}

m = -\frac{17.978}{1609.344}

Multiply by 1000/1000

m = -\frac{17.978 * 1000}{1609.344*1000}

m = -\frac{17978}{1609344}

The equation is then calculated using:

P - P_1 = m(h - h_1)

Substitute values for m, h1 and P1

P - P_1 = m(h - h_1)

P - 101.325 = -\frac{17978}{1609344}(h - 0)

P - 101.325 = -\frac{17978}{1609344}(h)

Make P the subject

P = -\frac{17978}{1609344}(h)+101.325

<em>The above is the required linear equation</em>

8 0
3 years ago
6.
Vikentia [17]

Answer:

Explanation:

Givens

vi = 0

a = 9.81

d = 4.50 m

vf = ?

Formula

vf^2 = vi^2 + 2 * a * d

Solution

Substitute the knowns into the formula

vf^2 =0 +  2 * 9.81 * 4.50

vf^2 = 88.29                          Take the square root of both sides.

sqrt(vf^2) = sqrt(88.29)    

vf = 9.40 m/s

3 0
3 years ago
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