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madreJ [45]
3 years ago
15

The relationship between angular acceleration α and torque τ is given by blank, where I is the moment of inertia., where I is th

e moment of inertia.
Physics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

\tau=I\times \alpha

Explanation:

The relationship between angular acceleration α and torque τ is given by :

\tau=I\times \alpha

Here,

I is the moment of inertia. It depends on the mass and the distance from the axis of rotation.

\alpha is the angular acceleration

Hence, this is the required solution.

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what is the rotational kinetic energy of the earth? use the moment of inertia you calculated in part a rather than the actual mo
Ivenika [448]

The Earth's rotational kinetic energy is the kinetic Energy that the Earth

has due to rotation.

The rotational kinetic energy of the Earth is approximately <u>3.331 × 10³⁶ J</u>

Reasons:

<em>The parameters required for the question are;  </em>

<em>Mass of the Earth, M = </em><em>5.97 × 10²⁴ kg</em>

<em>Radius of the Earth, R = </em><em>6.38 × 10⁶ m</em>

<em>The rotational period of the Earth, T = </em><em>24.0 hrs</em><em>.</em>

The \ moment  \ of \  inertia \  of \  uniform \  sphere \  is \ I =   \mathbf{\dfrac{2}{5} \cdot M \cdot R^2}

Which gives;

\mathbf{I_{Earth}} =   \dfrac{2}{5} \times 5.97 \times 10 ^{24} \cdot \left(6.38 \times 10^6 \right)^2 = 9.7202107 \times 10^{37}

\mathrm{The \ rotational \  kinetic  \ energy \  is} \   E_{rotational} = \mathbf{\dfrac{1}{2} \cdot I \cdot \omega^2}

\mathrm{The \ angular \ speed, \ \omega} = \mathbf{\dfrac{2 \dcdot \pi}{T}}

Therefore;

\omega = \dfrac{2 \cdot \pi}{24}  = \dfrac{\pi}{24}

Which gives;

\mathbf{E_{rotational}} = \dfrac{1}{2} \times  9.7202107 \times 10^{37} \times  \left(  \dfrac{\pi}{12} \right)^2 = 3.331 \times 10^{36}

The rotational kinetic energy of the Earth, E_{rotational} = <u>3.331 × 10³⁶ Joules</u>

Learn more here:

brainly.com/question/13623190

<em>The moment of inertia from part A  of the question (obtained online) is that of the Earth approximated to a perfect sphere</em>.

<em>Mass of the Earth, M = 5.97 × 10²⁴ kg</em>

<em>Radius of the Earth, R = 6.38 × 10⁶ m</em>

<em>The rotational period of the Earth, T = 24.0 hrs</em>

3 0
3 years ago
Two masses are connected by a string which passes over a pulley with negligible mass and friction. One mass hangs vertically and
monitta

Answer:

a=2,5m/s^2

Explanation:

From the question we are told that:

Coefficient of kinetic friction \mu= 0.200

Vertical Mass M_v=3kg

Horizontal mass M_h=3.00kg  

Generally the equation for kinetic force F_k is mathematically given by

F_k=\mu N\\F_k=0.2*3\\F_k=0.6

Generally the equation for T is mathematically given by

For M_v=3kg3g-T=3a

For M_h=3kg

T=M_v V+F_k\\T=3.0a+0.6

Therefore substituting

3-3a-0.6=3a\\2.4g=6a

a=2,5m/s^2

3 0
3 years ago
(1.) When aqueous solutions of Fe(NO3)3 and NaOH are mixed, Fe(OH)3 and NaNO3 are formed. is there a precipitate formed? if yes,
andriy [413]

From the solubility rules, both reactions 1 and 2 lead to precipitates.

<h3>What is a precipitate?</h3>

The term precipitate refers to the solid that separates out of the reaction mixture . We know that the solubility of a substance in water is predicated on the solubility rules.

1) The reaction here is;

Fe(NO3)3(aq) +  3NaOH(aq) ------> Fe(OH)3(s) + 3NaNO3(aq) - The precipitate is  Fe(OH)3 because only the hydroxides of group 1 elements are soluble in water.

2) The reaction is;

Pb(NO3)2(aq) + 2KI(aq) ----->PbI2(s) + 2NaNO3(aq) - The precipitate is PbI2 because most iodides are soluble except the iodides of  Ag+, Hg+2, and Pb+2

Complete Ionic equation;

Pb^2+(aq) + 2NO3^-(aq) + 2K^+(aq) + 2I^-(aq) ------> PbI2(s) +  2NO3^-(aq) + 2K^+(aq)

Net ionic equation;

Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)

Learn more about the solubility rules:brainly.com/question/12978582

##SPJ1

4 0
2 years ago
Water pumps use electrical energy to create mechanical energy needed to move water.
Afina-wow [57]

Answer:

n/a

Explanation:

this question is not feasible

3 0
2 years ago
The vertical normal stress increase caused by a point load of 10 kN acting on the ground surface at a point 1m vertically below
Tomtit [17]

Answer:

(b) 4.775 kN

Explanation:

see the attached file

8 0
3 years ago
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