Answer:
<em>The ball will go as high as 8.46 m</em>
Explanation:
<u>Projectile Motion</u>
It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:
The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of 
, then:
The ball will go as high as 8.46 m
Answer:
g' = g/9 = 1.09 m/s²
Explanation:
The magnitude of free fall acceleration at the surface of earth is given by the following formula:
g = GM/R² ----- equation 1
where,
g = free fall acceleration
G = Universal Gravitational Constant
M = Mass of Earth
R = Distance between the center of earth and the object
So, in our case,
R = R + 2 R = 3 R
Therefore,
g' = GM/(3R)²
g' = (1/9) GM/R²
using equation 1:
g' = g/9
g' = (9.8 m/s)/9
<u>g' = 1.09 m/s²</u>
In order to find the radius of the coin, we need to use:
Ac = V^2 r
In which,
Ac = acceleration of the coin = 2.2 m/s^2
V= rotational Speed = (18/12) * 2πr
r= Radius
so,
<span>2.2 = 9(π^2)(r^2) / r
</span><span>= 9(π^2)r
</span>
<span>r = 2.2 / 9(π^2) = 0.02476740044 m . . .or you can rounded it up to 0.025 m</span>
Hello there.
<span>Which of the following scenarios would cause a sound to stop being produced?
</span><span>A. The vibration results in a molecule moving vertically.
</span>
