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2 years ago

What is the length of EF?

Mathematics

1 answer:

yawa3891 [41]2 years ago

8 0

Answer:

Step-by-step explanation:

the measure DF is 7

DE = 2

to get EF, you have to subtract 2 from 7

7 - 2 = 5

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Rewrite the formula to find w.

sveta [45]

Answer:

P / 30 - 21= 9

2w = 9

w = 4.5

This should be the answer

4 0

3 years ago

If a worker can do his job in 5 hours, and a student can do the same job in 8 hours, what part of the work is left to finish aft

Aleks [24]

Answer:

Part of work left to finish after two work hours is 7/20

Step-by-step explanation:

Firstly, we need to calculate their joint work rate

That will be;

1/(1/5 + 1/8) = 1/(13/40) = 40/13

This means that they will complete the task in 40/13 hours

1 whole part takes 40/13

x part will take 2 hours

x * 40/13 = 2

40x = 26

x = 26/40

So the part that will be completed in two hours is 26/40

This means that the part left to complete will be:

1 - 26/40 = 14/40 = 7/20

8 0

2 years ago

Read 2 more answers

By what number should 1 1/2 be divided to get 2/3 ? *

andrew-mc [135]

Answer:

Step-by-step explanation:

1) The equation is 1 1/2 ÷ x = 2/3

2) You can multiply 2/3 with 1 1/2 to get your answer

3) 2/3 × 1 1/2 = 1

Hope this helps!

4 0

2 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

(12x - 2y + 3/5) - (1/4 - 8x + 6y)

Neko [114]

Answer:

20x-8y+ 7/20

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers