Question

A quadratic equation of the form 0=ax2 bx c has a discriminant value of -16. how many real number solutions does the equation have?

Answer 1

The given quadratic equation has no real solutions.

Given quadratic equation is:

$ax^2+bx+c=0$

What does the discriminant of a quadratic equation tell?

The discriminant(D) of a quadratic equation tells about the nature of roots.

If $D > 0$, the roots of the quadratic equation will be real and distinct.

If $D=0$, the roots of the quadratic equation will be real and equal.

If $D < 0$,  the roots of the quadratic equation will be imaginary.

Given that the quadratic $ax^2+bx+c=0$ has a discriminant value of -16.

$D=-16 < 0$

So, the roots of the given quadratic equation will be imaginary.

So, the given quadratic equation has zero real solutions.

Hence, the given quadratic equation has no real solutions.

To get more about quadratic equations visit:

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