3 years ago

Help me pleaseeeeeeee

Mathematics

1 answer:

brilliants [131]3 years ago

8 0

Don’t fall for the bitly it causes a virus be careful please

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Find the 50th term of the sequence 5,-2,-9,-16

sattari [20]

Answer:

50th term is -338

Step-by-step explanation:

Common difference d = -2-5 = -7

first term is a1 = 5

50th term

a50 = a1 + (n -1)d

a50 = 5 -7(50-1)

a50 = 5 -7(49)

a50 = -338

Hope this will helpful.

Thank you.

6 0

3 years ago

Will mark brainiest

vagabundo [1.1K]

Answer:

the right answer is d.

just use CAST relation

8 0

3 years ago

Read 2 more answers

2 EASY QUESTIONS HELP

Leona [35]

Answer:

a) 5/8

b)6/7

Step-by-step explanation:

3 0

3 years ago

The average high temperature in Valerie's city during the month of December is 50°F.

tino4ka555 [31]

Answer:

Step-by-step explanation:

50-32=18

8 0

3 years ago

In each of the following ,make y the subject and hence find the value of y when a=2, b=3 ,and c=4.

zvonat [6]

Part i

$\dfrac{2a-7}{6y} = \dfrac{3b-5}{2c}$

$y = \dfrac{ 2c(2a-7)}{6(3b-5)} = \dfrac{c(2a-7)}{9b-15}$

Substituting,

$y = \dfrac{4(2(2)-7)}{9(3)-15} = \dfrac{ -12}{12} = -1$

Answer: -1

Part ii

I'm not sure that one's typed in correctly but I'll solve it as written.

$3-34y + 2a = \dfrac{3b-5}{2c + 1}$

$34y = 3+2a-\dfrac{3b-5}{2c + 1}$

$y = \frac 1 {34}\left(3+2a-\dfrac{3b-5}{2c + 1} \right)$

We're not asked to simplify it so I wont. Substituting,

$y = \frac 1 {34}\left(3+2(2)-\dfrac{3(3)-5}{2(4) + 1} \right) = \frac 1 {34}(7-4/9) = \dfrac{59}{306}$

Answer: 59/306

3 0

3 years ago