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adoni [48]
3 years ago
7

The slope of line x = 6

Mathematics
1 answer:
yulyashka [42]3 years ago
6 0
X = 6 is vertical, so it has infinite slope
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Please help me
oee [108]

Answer:

0,3

Step-by-step explanation:

5 0
3 years ago
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Find the slope of the line that passes through the points (-6, -2) and (-7, -2)
SVEN [57.7K]
(-6, -2)/(-7, -2)
y-y/x-x
(-2- -6)/(-2- -7)
(-2+6)/(-2+7)
4/5 = slope
7 0
3 years ago
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I don't really know what to do for this one.
Colt1911 [192]
Let, Price of a shirt = x
Price of a Jeans = y

Equations would be: 4x + 3y = 150
x + 2y = 70
x = 70-2y

Substitute it into first equation, 
4(70-2y) + 3y = 150
280 - 8y + 3y = 150
-5y = -130
y = 130/5
y = 26

Substitute it into 2nd equation, 
x + 2(26) = 70
x = 70-52
x = 18

So, Cost of a Shirt = $18  &  Cost of a Jeans = $26

Hope this helps!
3 0
3 years ago
Lauren is reading a novel for English class. The data below shows the number of pages reads, y, in x hours.
strojnjashka [21]

Answer:

Choice B is correct

Step-by-step explanation:

The variable x represents the number of hours;

2, 4, 5, 7, 9

The least value is 2 while the maximum value is 9. The scale to be used must accommodate all these values. The scale can thus begin from 0 to 10. Choice A is incorrect since the values 7 and 9 will not be accommodated in the graph.

The y variable represents the number of pages read;

50, 100, 125, 175, 225

The least value is 50 while the maximum value is 225. The scale to be used must accommodate all these values. The scale can thus begin from 0 to 250. Both choices C and D are incorrect since none of the values will be accommodated in the graph.

7 0
3 years ago
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Which function represents the graph of h(x)=2|x+3|−1 after it is translated 2 units right?
harina [27]

\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}

\bf ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}

\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}

now with that template in mind

\bf h(x)=\stackrel{A}{2}|\stackrel{B}{1}x+\stackrel{C}{3}|\stackrel{D}{-1}\qquad \qquad \stackrel{\textit{C=C-2 a translation to the right}}{h(x)=2|x\boxed{+3-2}|-1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill h(x)=2|x+1|-1~\hfill

8 0
4 years ago
Read 2 more answers
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