If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
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P(
successes in 
trials) = ⁿ
×![[P(Success)^{r}]](https://tex.z-dn.net/?f=%20%5BP%28Success%29%5E%7Br%7D%5D%20)
×![[P(failure)]^{n-r}](https://tex.z-dn.net/?f=%20%5BP%28failure%29%5D%5E%7Bn-r%7D%20)
We have
Substitute these values into the formula, we have
P( 2 success in 8 trials) = ⁸C₂ × (0.15)² × (0.85)⁶
P( 2 success in 8 trials) = 0.2376.... ≈ 0.24 = 24%
We have
Substitute these values into the formula, we have
P( 2 success in 8 trials) = ⁸C₂ × (0.15)² × (0.85)⁶
P( 2 success in 8 trials) = 0.2376.... ≈ 0.24 = 24%