Ask question

Ask question

All categories

elena-14-01-66 [18.8K]

3 years ago

6

Ms.Rochelle wants to put her 29 students into groups of 6. How many groups of 6 can she make? If she puts any remaining students

in a smaller group, how many students will be in that group?

1 answer:

alukav5142 [94]3 years ago

8 0

Answer:

A. 4 groups of 6 students in each group.

B. The smaller group will have 5 students.

Step-by-step explanation:

We have been given that Ms.Rochelle wants to put her 29 students into groups of 6.

A. To find the number of groups of 6 that can be made from 29 students, we will find the greatest multiple of 6 from 29.

Multiples of 6 are: 6, 12, 18, 24, 30, 36,...

We can see that the greatest multiples of 6 in 29 in 24.

$\text{Number of groups that can be made with 29 students}=\frac{24}{6}$

$\text{Number of groups that can be made with 29 students}=4$

Therefore, Ms. Rochelle can form 4 groups from 29 students with 6 students in each group.

B. To find the number of students in small group, we will subtract 24 from 29.

$\text{Number of students in the small group}=29-24$

$\text{Number of students in the small group}=5$

Therefore, If Ms. Rochelle puts any remaining students in a smaller group, the number of students in smaller group will be 5.

You might be interested in

Shira's math test included a survey question asking how many hours students spent studying for the test. The scatter plot below

andre [41]

Answer:

10x+45

Step-by-step explanation:

8 0

3 years ago

In this figure, a and b are<br>A. vertical<br>B. equal<br>C. complementary.<br>D. supplementary.

Andreas93 [3]

It is a supplementary angle. D because the add up to 180.

8 0

3 years ago

Can someone help with this please

Lady_Fox [76]

Answer:

DFE

Step-by-step explanation:

4 0

2 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

Geometry Question Need Help. I will give brainliest

Dafna1 [17]

Answer:

-4 + 5 + 1 is your answer I am the teacher of your Colony

7 0

3 years ago