End behavior: f. As x -> 2, f(x) -> ∞; As x -> ∞, f(x) -> -∞
x-intercept: a. (3, 0)
Range: p. (-∞, ∞)
The range is the set of all possible y-values
Asymptote: x = 2
Transformation: l. right 2
with respect to the next parent function:

Domain: g. x > 2
The domain is the set of all possible x-values
2 committees. 6 is divisible by 3 twice, 8 is divisible by 4 twice.
Answer:
Probability that first sock is blue is 0.33 and Probability that second sock is red is 0.16
Step-by-step explanation:
Number of red socks = 2
Number of white socks = 6
Number of blue socks = 4
Total socks in drawer = 2+6+4 = 12
The formula used to calculate probability is: 
We are given you draw out a sock, return it, and draw out a second sock.
We need to find the probability that the first sock is blue and the second sock is red?
Using formula:
Probability that first sock is blue = 4/12 = 1/3 = 0.33
Probability that second sock is red = 2/12 = 1/6 = 0.16
So, Probability that first sock is blue is 0.33 and Probability that second sock is red is 0.16
Answer:
9
Step-by-step explanation:
I would guess it looks like this - if not then tell me

2×3=6
5-2=3
Then there's only

Which is equal to
