All categories

3 years ago

What would the answer for this question be

Mathematics

1 answer:

Yakvenalex [24]3 years ago

5 0

THE ANSWER IS SIN C SOH OPPosit out of hypo

You might be interested in

The table shows the values of a function f(x).

QveST [7]

Answer:

The average rate of change is $=-4$

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is given by;

$=\frac{f(b)-f(a)}{b-a}$

We want to find the average rate of change of the function represented in the table from x=-2 to x=2.

$=\frac{f(2)-f(-2)}{2--2}$

From the table f(-2)=25 and f(2)=9

The average rate of change from x=-2 to x=2 is

$=\frac{9-25}{2--2}$

$=\frac{-16}{4}$

$=-4$

3 0

3 years ago

In ΔKLM, the measure of ∠M=90°, LK = 97, ML = 65, and KM = 72. What is the value of the sine of ∠L to the nearest hundredth?

Sphinxa [80]

Answer:

0.74

Step-by-step explanation:

72/97 is 0.74 rounded to the nearest hundredths.

6 0

3 years ago

Sally can paint a room in 7 hours while it takes Steve 6 hours to paint the same room. How long would it take them to paint the

Kipish [7]

I would say about 6.25 hours

6 0

3 years ago

Read 2 more answers

What is the value of x?

Trava [24]

The sum of a polygon's angles are 540.

When you add all the angles together here, you get 456.

Now subtract 456 from 540.

540 - 456 = 84

7 0

3 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago