What is the cosecant of angle X?
1 answer:
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now, with that template in mind, let's check this one
A = -1, reflection over the x-axis.
B = 1, C = +3, C/B = +3/1 = +3, horizontal shift to the left of 3 units.
D = 5, vertical shift up of 5 units.
Answer:
Hope I'm not too late for this...
(look below)
Step-by-step explanation:
For the first part:
1. b = -1, m = 2
The y-intercept (b) is the value of y when x = 0. In this case, we can see that when x = 0, y = -1 so the y-intercept is -1.
The slope was found using the equation slope (m) = (y2-y1) / (x2-x1) and two points. (Note, you can choose any two points, I just chose the first two.)
(5,9) (-2,-5)
slope = (y2-y1) / (x2-x1)
slope = (-5-9) / (-2-5)
slope = -14/-7
slope = 2
I used the same steps as shown above:
2. b = 2, m = -3
For the second part:
1. y = 2x - 1
2.y = -3x + 2
I basically plugged in the values for m and b into the equation, y = mx + b.
Graphs:
The way to graph a line is to plot at least two points and draw a line through them. You can graph it using either the equation or the table. I used the table since it is much easier to find the points that I need.
Below I have included references to what the graph should look like if you need to check your work.
The one in blue is for the equation y = 2x - 1. This should help you get a visual of what the correct graph looks like.
The one in green is for the equation y = -3x + 2.
I hope this helped!
