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svlad2 [7]
3 years ago
5

​ y=2x+3 y=−3x+3 ​ find slope and y-intercept

Mathematics
1 answer:
german3 years ago
6 0

Answer:

y = 2x + 3  → Gradient / slope = 2 → Y - intercept = 3

y = -3x + 3 → Gradient / slope = -3 → Y - intercept = 3

Step-by-step explanation:

y = mx + c

This is the standard way an equation of a line is written. The 'm' of the line is the slope/gradient and the 'c' is the y - intercept. You can find the x-intercept by making y = 0. When the questions asks you to find the gradient you should never put 'x' after it only the number so

y = 2x + 3

Gradient / slope = 2

Y - intercept = 3

y = -3x + 3

Gradient / slope = -3

Y - intercept = 3

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A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true
kvv77 [185]

Answer:

99.74% probability that the sample proportion will be less than 0.1

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

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Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 276, p = 0.06

So

\mu = E(X) = np = 276*0.06 = 16.56

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{276*0.06*0.94} = 3.9454

What is the probability that the sample proportion will be less than 0.1

This is the pvalue of Z when X = 0.1*276 = 27.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{27.6 - 16.56}{3.9454}

Z = 2.8

Z = 2.8 has a pvalue of 0.9974

99.74% probability that the sample proportion will be less than 0.1

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3 years ago
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earnstyle [38]
The answer for this is 60
6 0
3 years ago
Estimate the product 8.91 × 34,871.081
aleksklad [387]
The way I would do it is by rounding 8.91 up to 9 and I would round 34,871.081 up to 35,000.
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Hopefully I was able to help in some way.
3 0
3 years ago
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drek231 [11]
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