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Naya [18.7K]
3 years ago
9

Use the graph below to fill in the blank with the correct number:

Mathematics
1 answer:
astraxan [27]3 years ago
6 0

Answer: f(0) should fit on the graph under 2.5

Step-by-step explanation:

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Can someone help me please
IgorLugansk [536]

Answer:

B

Step-by-step explanation:

The slope is 4.

Let's find the slope between your two points.

(1,−2); (3,6)

(x1,y1) = (1,−2)

(x2,y2) = (3,6)

Use the slope formula:

m = y2−y1 / x2−x1

= 6− −2 / 3−1

= 8 / 2

= 4

Answer:

m = 4

7 0
2 years ago
Read 2 more answers
Please help me I’m doing a test and it’s very hard to me please it’s worth 200 point of my grade
Nana76 [90]

Answer:

y = 15x

Step-by-step explanation:

For every hour that has gone by, Marco biked 15 miles, therefore, the equation of the line that shows the relationship between the time, x, and the distance, y, is <em>y = 15x</em>.

6 0
3 years ago
Which equation can be used to solve for x in the following diagram.
Leokris [45]
I don’t see an attachment for a diagram
6 0
3 years ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
2 years ago
Please help me ASAP
Salsk061 [2.6K]

Answer:

Two.

Step-by-step explanation:

Simultaneous equation is a Finite sets of equations whose common solutions are sought.

Two solutions in the equation above is sought.

5 0
3 years ago
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