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lora16 [44]
3 years ago
5

Keith bought a package with 2 9/16 pounds of ground meat to make hamburgers. He has 2/5 pound of ground meat left. About how man

y pounds of ground meet did he use for the hamburgers?
Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
2 13/80 punds of ground meet
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A sledgehammer weighs 18 pounds on Earth and 4 pounds on the planet Namar. Which of the following proportions could you use to d
ryzh [129]
4/18=x/100 is a proportion you can use 
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"Which diagram below shows the first step in parallel line construction on a point outside a line?
mote1985 [20]

<u>Answer</u>

2nd diagram


<u>Explanation.</u>

When contraction a parallel line from a point say N, outside the line, the first thing is to draw a line from point N to the that line.

The point where this line from N intersect with line, name it say P. From this point you can use the properties of angles in a parallel lines to construct the parallel line.

The line NP can act like a transverse of the two parallel lines. The diagram 2 shows first step.


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Craig is tiling the floor of his bathroom. He wants 1/4 of the tiles to be brown. What other fractions can represent the part of
Julli [10]
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4 years ago
---- PLEASE HELP &lt;3 .. with steps :( &lt;3
Zielflug [23.3K]

1) 6, 18, 54

2) 5/3, 14/9, 41/27

3) 1.5, 2.5, 2.5

Step-by-step explanation:

1)

The function that we have in this problem is

g(x)=3x

We want to find the first 3 iterations.

The initial value is:

x = 2

To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:

g_1(x)=3x=3\cdot 2 = 6

The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:

g_2(x)=3\cdot g_1(x)=3\cdot 6 = 18

Finally, the 3rd iteraction is given by:

g_3(x)=3g_2(x)=3\cdot 18=54

2)

Here in this problem the function that we have to use is

g(x)=\frac{1}{3}x+1

The initial value is

x=2

So the first iteration is given by

g_1(x)=\frac{1}{3}\cdot 2 + 1 = \frac{5}{3}

To find the 2nd iteration, we substitute this value into g(x) again:

g_2(x)=\frac{1}{3}g_1+1=\frac{1}{3}\cdot \frac{5}{3}+1=\frac{5}{9}+1=\frac{14}{9}

Finally, to find the 3rd iteration, we substitute this value into g(x) again:

g_3(x)=\frac{1}{3}\cdot \frac{14}{9}+1=\frac{14}{27}+1=\frac{41}{27}

3)

The function in this problem is

g(x)=-|x-2|+3

The initial value is

x = 0.5

So, the first iteration is:

g_1(x)=-1|0.5-2|+3=-1|-1.5|+3=-1\cdot 1.5 +3=-1.5+3=1.5

The second iteration is given by

g_2(x)=-|g_1-2|+3=-|1.5-2|+3=--0.5+3=2.5

Finally, the 3rd iteration is

g_3(x)=-|g_2-2|+3=-|2.5-2|+3=-0.5+3=2.5

5 0
3 years ago
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