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3 years ago

10

Which symbol correctly compares these fractions? 3 7 ___ 5 14 < > = ×

1 answer:

GarryVolchara [31]3 years ago

7 0

$\frac{3}{7}$ is more than $\frac{5}{14}$ , because:
$\frac{3}{7}$ = $\frac{6}{14}$
6>5

So, the correct sign for this is >.
Have a great day! ♪

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denpristay [2]

Answer:

-40

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3 years ago

What is an estimate for 17 divided by 1569

Y_Kistochka [10]

It will be 93 because it 92 but you have to round up with deimal number

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4 years ago

Read 2 more answers

-4rover4+5rover3 please help me

Alchen [17]

$Solution, \frac{-4r}{4}+\frac{5r}{3}=\frac{2r}{3}$

$Steps:$

$\frac{-4r}{4}+\frac{5r}{3}$

$\frac{-4r}{4},\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b},\\-\frac{4r}{4},\\\mathrm{Divide\:the\:numbers:}\:\frac{4}{4}=1,\\-r,\\-r+\frac{5r}{3}$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:r=\frac{r3}{3},\\\frac{5r}{3}-\frac{r\cdot \:3}{3}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c},\\\frac{5r-r\cdot \:3}{3}$

$5r-r\cdot \:3,\\\mathrm{Add\:similar\:elements:}\:5r-3r=2r,\\\frac{2r}{3}$

$The\:Correct\:Answer\:Is\:\frac{2r}{3}$

$Hope\:This\:Helps!!!$

$-Austint1414$

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3 years ago

Quadrilateral ABCD is similar to Quadrilateral EFGH. The scale factor is 3:2 if AB = 18, find EF

Marina86 [1]

Answer:

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Step-by-step explanation:

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2 years ago

Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05

exis [7]

we are given

$f(x)=\frac{x^2-5x}{x^2-x-20}$

Firstly, we will simplify it

$f(x)=\frac{x(x-5)}{(x-5)(x+4)}$

$f(x)=\frac{x}{(x+4)}$

At x=5.5:

we can plug x=5.5

$f(5.5)=\frac{5.5}{(5.5+4)}$

$f(5.5)=0.578947$

At x=5.1:

we can plug x=5.1

$f(5.1)=\frac{5.1}{(5.1+4)}$

$f(5.1)=0.56043956$

At x=5.05:

we can plug x=5.05

$f(5.05)=\frac{5.05}{(5.05+4)}$

$f(5.05)=0.558011$

At x=5.01:

we can plug x=5.01

$f(5.01)=\frac{5.01}{(5.01+4)}$

$f(5.01)=0.5560488$

At x=5.005:

we can plug x=5.005

$f(5.005)=\frac{5.005}{(5.005+4)}$

$f(5.005)=0.5558023$

At x=5.001:

we can plug x=5.001

$f(5.001)=\frac{5.001}{(5.001+4)}$

$f(5.001)=0.5556049$

At x=4.9:

we can plug x=4.9

$f(4.9)=\frac{4.9}{(4.9+4)}$

$f(4.9)=0.5505617$

At x=4.95:

we can plug x=4.95

$f(4.95)=\frac{4.95}{(4.95+4)}$

$f(4.95)=0.5530726$

At x=4.99:

we can plug x=4.99

$f(4.99)=\frac{4.99}{(4.99+4)}$

$f(4.99)=0.55506117$

At x=4.995:

we can plug x=4.995

$f(4.995)=\frac{4.995}{(4.995+4)}$

$f(4.995)=0.55503085$

At x=4.999:

we can plug x=4.999

$f(4.999)=\frac{4.999}{(4.999+4)}$

$f(4.999)=0.55550616$

7 0

4 years ago