To solve this problem you must apply the proccedure shown below:
1. You have that the formula for calculate the area of a triangle is:
A=bh/2
Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.
bh/2=124
bh=124x2
bh=248
2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:
Base=b/2
Height=3h
3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:
A'=bh/2
(A' is the new area)
A'=(b/2)(3)/2
A'=3bh/4
4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
A'=186 units</span>²
<span>
The answer is: </span>186 units²
Answer:
9 x (x +5) = 185
Step-by-step explanation:
I'm pretty sure this is how you write it
Answer:
8 and 5
Step-by-step explanation:
Let b= length and a=width
Area= a*b and the problem said b=2a+3 (the length is 3ft more than double the width)
Replace b into Area formula:
Area= a*(2a+3) and we know that Area=77ft from the problem, so:
77=2a^2+3a now order and equal to zero:
2a^2+3a=77 now solve this with quadratic formula and you will get so values for a: -7ft and 5.5ft as you know the dimensions could not be negative so the correct answer for "a" side is 5.5ft, for getting the b side you haeve to replace a=5.5 into b=2a+3 and you will get b=2*5.5+3= 14ft.
Finished.
