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vovikov84 [41]
3 years ago
9

Show that the maximum rate of change, with respect to radius, of the volume of a deflating balloon is four times the sphere's in

itial great circle circumference
Mathematics
1 answer:
dmitriy555 [2]3 years ago
7 0

Step-by-step explanation:

Let's say R is the initial radius of the sphere, and r is the radius at time t.

The volume of the sphere at time t is:

V = 4/3 π r³

Taking derivative with respect to radius:

dV/dr = 4π r²

This is a maximum when r is a maximum, which is when r = R.

(dV/dr)max = 4π R²

This is 4 times the sphere's initial great circle area, but not the great circle circumference.  The problem statement contains an error.

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A circular trampoline has a radius of 8 feet. Wendy wants to buy a cover for the trampoline. What will be the area of the cover?
marusya05 [52]

Answer:

64π square feet (the formula for the area is r^2π so you have to multiply 8 with itself and you get 64. 64×π is 64π)

7 0
4 years ago
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Does Y=3/X represent a linear function when X=0
Elis [28]
Hello,

Divide by 0 is impossible.
So when x=0; y is undefined.

<span>Therefore, y cannot be a linear function.</span>
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3 years ago
How do I even start?!
OlgaM077 [116]
For #1 you know that a straight line equalys 180 degrees so the look at the 3× degrees. 180-84 =96 /3= 32 degrees . x = 32
8 0
3 years ago
Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.​
Galina-37 [17]

Question:

Prove that:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Answer:

Proved

Step-by-step explanation:

Given

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Required

Prove

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Subtract tan(10) from both sides

- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

Factorize the right hand size

tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)

Rewrite as:

tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))

Divide both sides by 1-tan(70). tan(100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)

In trigonometry:

tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}

So:

\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)} can be expressed as: tan(70 + 100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10) gives

tan(70 + 100) = -tan(10)

tan(170) = -tan(10)

In trigonometry:

tan(180 - \theta) = -tan(\theta)

So:

tan(180 - 10) = -tan(10)

Because RHS = LHS

Then:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) has been proven

6 0
3 years ago
Every month Jimmy makes $170 in mowing lawns. He divides his money into two equal amounts and spends one part. The other part go
elena55 [62]

Answer:

$1020

Step-by-step explanation:

1/2 of 170 is 85.

85 x 12 = 1020

WOOOO!!!!

092MLBO

7 0
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