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Mars2501 [29]
3 years ago
5

Is the point (4,2) the solution to the system? Why or why not? Explain your reasoning.

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0
Solve the top equation to get on variable on one side
2x-y=6
-y=-2x+6
y=2x-6
then plug in the coordinate for x and y for both equations. if both equations are true then it’s a solution
2=2(2)+6
2=10

4+2=6

so it’s not a solution
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Which equation represents the polynomial function with zeros −1, 1, and 3 (multiplicity of 2), and a y-intercept of −18? (4 poin
Vlad [161]
Correct Answer:
3rd option is the correct answer

Solution:
The zeros of the polynomial are -1,1 and 3. The multiplicity of 3 is 2. So the polynomial can be expressed as:

y=a (x-3)^{2}(x-1)(x+1)

The y-intercept of the polynomial is -18. This means the polynomial passes through the point (0,-18). Therefore, y must be -18 when x = 0. Using these values of x and y in previous equation we get:

-18=a (0-3)^{2}(0-1)(0+1) \\  \\ 
-18=-9a \\  \\ 
a=2

The final equation of the polynomial becomes:

y=2 (x-3)^{2}(x-1)(x+1)

7 0
3 years ago
Easy easy point answer the question
Gala2k [10]

Answer:

2 7/8

Step-by-step explanation:

4 0
3 years ago
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5 0
3 years ago
The sign shows distances from a rest stop to the exits for different towns along a straight section of highway. The state depart
torisob [31]
Refer to the diagram shown below.

The exit for Freestone is built midway between Roseville and Edgewood,
therefore the distance from O to the new exit is
(1/2)*(33+55) = 44 mi.

Let x =  distance from Midtown to the new exit.
Because the distance from O to the new exit is equal to (x + 17), therefore
x + 17 = 44
x = 44 - 17 = 27 mi.

Answer:
When the new exit is built, the distance from the exit for Midtown to the exit for Freestone will be 27 miles.

3 0
3 years ago
Whats the answer to 2y^0-(3y)^0
mrs_skeptik [129]

Answer:

1

Step-by-step explanation:

To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:

2y^0 - (3y)^0

= 2(1) - (1)

= <u>1</u>

<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>2</em><em>y</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>y</em><em>^</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>1</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>w</em><em>h</em><em>e</em><em>r</em><em>e</em><em>a</em><em>s</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>2</em><em>y</em><em>)</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em>

6 0
3 years ago
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