10g = 4/6....divide both sides by 10
g = (4/6) / 10
g = 4/6 * 1/10
g = 4/60 which reduces to 1/15 <==
Answer:
The answer in the procedure
Step-by-step explanation:
we have
![2=-x+x^{2} -4](https://tex.z-dn.net/?f=2%3D-x%2Bx%5E%7B2%7D%20-4)
![x^{2}-x-4-2=0](https://tex.z-dn.net/?f=x%5E%7B2%7D-x-4-2%3D0)
![x^{2}-x-6=0](https://tex.z-dn.net/?f=x%5E%7B2%7D-x-6%3D0)
we know that
The formula to solve a quadratic equation of the form
is equal to
![x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%28%2B%2F-%29%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
in this problem we have
![x^{2}-x-6=0](https://tex.z-dn.net/?f=x%5E%7B2%7D-x-6%3D0)
so
![a=1\\b=-1\\c=-6](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D-1%5C%5Cc%3D-6)
substitute in the formula
![x=\frac{-(-1)(+/-)\sqrt{(-1)^{2}-4(1)(-6)}} {2(1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-1%29%28%2B%2F-%29%5Csqrt%7B%28-1%29%5E%7B2%7D-4%281%29%28-6%29%7D%7D%20%7B2%281%29%7D)
![x=\frac{1(+/-)\sqrt{25}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%28%2B%2F-%29%5Csqrt%7B25%7D%7D%20%7B2%7D)
![x=\frac{1(+/-)5} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%28%2B%2F-%295%7D%20%7B2%7D)
![x=\frac{1(+)5} {2}=3](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%28%2B%295%7D%20%7B2%7D%3D3)
![x=\frac{1(-)5} {2}=-2](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%28-%295%7D%20%7B2%7D%3D-2)
Answer:
see explanation
Step-by-step explanation:
Since lines a and b are parallel, then
∠NMP and ∠MPQ are same side interior angles and are supplementary, thus
a + a - 20 = 180
2a - 20 = 180 ( add 20 to both sides )
2a = 200 ( divide both sides by 2 )
a = 100, hence
∠NMP = a = 100° and
∠MPQ = a - 20 = 100 - 20 = 80°
Answer:
Step-by-step explanation:
It says with a perpendicular to b and c that means that they are parallel and if they are both cut and perpenducular then they are both parallel.