Answer: t1 = -34; t2 = -64; t3 = -94
d is the distance between numbers (d > 0)
we have:
t5 = t1 + 4d = -154
t9 = t1 + 8d = -274
we have the equations:
t1 + 4d = -154
t1 + 8d = -274
<=> t1 = -34
d = -30
with t1 = -34 and = -30 => t2 = -34 - 30 = -64
t3 = -64 - 30 = -94
Step-by-step explanation:
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
Answer:
The domain would be given by <u>D = {X ≥ 2} X = [2, Z].</u> Since the variable Z is the number of children in the school. And the 6 children should not survey the same person, it would be Z / 6 for each interviewer.
Step-by-step explanation:
- If the group of children surveys more than 2 classmates, it means that the number with which the survey begins is 12 students.
And since the maximum number of students in the school is given by the variable of Z, then Z is the number with which the domain closes.
The rank would be given by the set of [2, Z]
Z / 6 being the maximum number of children surveyed by 1 interviewer.
Answer:
13000
Step-by-step explanation:
1 = 2,000 pounds
0.5 tons = 1000 pounds