Answer:
Weighted average is the average of a set of numbers, each with different associated “weights” or values. To find a weighted average, multiply each number by its weight, then add the results.
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
Option D. 
Step-by-step explanation:
step 1
Find the midpoint of the given line segment
we know that
The formula to calculate the midpoint between two points is equal to
 
we have

substitute the values
 
 
step 2
Find the equation of the perpendicular bisector
we know that
The equation of a perpendicular bisector is equal to the x-coordinate of the midpoint, because is a vertical line (parallel to the y-axis)
therefore
the equation is equal to

 
        
                    
             
        
        
        
<h3>Answer: 6pi radians</h3>
(this is equivalent to 1080 degrees)
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Explanation:
f(x) = sin(x/3)
is the same as
f(x) = 1*sin( (1/3)(x-0) )+0
and that is in the form
f(x) = A*sin( B(x-C) )+D
The letters A,B,C,D are explained below
A = helps find the amplitude
B = 2pi/T, where T is the period
C = determines phase shift (aka left/right shifting)
D = determines vertical shift = midline
All we care about is the value of B as that is the only thing that is connected to the period T
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Compare f(x) = 1*sin( (1/3)(x-0) )+0 with f(x) = A*sin( B(x-C) )+D and we see that B = 1/3, so,
B = 2pi/T
1/3 = 2pi/T
1*T = 3*2pi ... cross multiply
T = 6pi
The period is 6pi radians. This is equivalent to 1080 degrees. To convert from radians to degrees, you multiply by (180/pi).
 
        
        
        
Answer:
2
Step-by-step explanation:
The average rate of change over [2, 8] is the change in the y-values over the change in the x-values.




 
        
             
        
        
        
Answer:
a) weight  of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy  =  0     and  ∑Fx  =  0
Forces acting on the car:
The external force   490 lbs
weight of the car   uknown
Normal force
sin∠10°  =  0,174
cos∠10° = 0.985
∑Fx  =  0         mg*sin10°- 490 = 0      ∑Fy =  0      mg*cos10° - N  =  0
mg*0,174= 490
mg  =  490 / 0,174
mg = 2816,1 lbs
weight  of the car = 2816,1 lbs
The Normal force
 mg*cos10° - N  =  0        2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway