Find the accumulated value of an investment of $7000 at 12% compounded semiannually for 12 years.
1 answer:
Answer:
$28,342.54
Step-by-step explanation:
The value of an account earning compound interest is found using the formula ...
A = P(1 +r/n)^(nt)
where P is the principal invested at annual rate r compounded n times per year for t years.
__
You have P=7000, r=0.12, n=2, t=12.
Using these values in the formula, we find the accumulated value of the investment to be ...
A = 7000(1 +0.12/2)^(2·12) = 7000(1.06^24) ≈ 28,342.54
The value after 12 years is $28,342.54.
_____
<em>Additional comment</em>
The time-value-of-money functions of your calculator or spreadsheet can find this for you.
You might be interested in
Answer:
s(x) is t(x) ...
- horizontally compressed by a factor of 2,
- reflected across the y-axis, and
- translated downward 5 units.
Domain and Range
- t(x) has a domain of x ≤ 0, and a range of y ≥ 0.
- s(x) has a domain of x ≥ 0, and a range of y ≥ -5.
Step-by-step explanation:
t(x) is the square root function reflected across the y-axis and compressed horizontally by a factor of 2. That is, in f(x) = √x, the x has been replaced by -2x.
s(x) has the function t(x) <em>reflected back across the y-axis</em> and compressed horizontally by another factor of 2. It is also <em>translated downward by 5 units</em>, so that its origin (vertex) is at (0, -5).
_____
The graph shows you the domain and range of s(x). The domain is all numbers to the right of x=0, including x=0. That is ...
domain: x ≥ 0
The range is all numbers -5 or above:
range: y ≥ -5
___
For t(x), the argument of the square root function must not be negative, which means the value of x cannot be positive.
domain: x ≤ 0
For non-negative values of radicand, the t(x) function will have non-negative values. So, the range is ...
range: y ≥ 0
_____
<em>Comment on solving problems like this</em>
Your graphing calculator can be your friend.
Answer:
- C. P’s surface area is greater than Q’s surface area.
Step-by-step explanation:
<em>Refer to attached</em>
With a corner removed, it doesn't change surface area of the cube as same area is exposed equal to the area of 3 small faces.
With the corner relocated to the top of the cube, it covers the area of one small face but adds up small 5 faces (4 sides and one top). In total the P has more surface area than the Q.
Correct answer choice is C.
