Find the area of the parallelogram of A=
2 answers:
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In solving this problem we can consider Earth to be a sphere. When we have a circle, then we can use this formula to find arc length:
Where:
L= arc length (in this problem it is disance we need to travel)
R = radius of circle (in this problem it is equal to a radius of Earth)
C = angle we need to pass
We are told that two cities lie halfway around the world. If we fly to west this means angle is 180°.
This gives an arc length of:
If we want to fly to north we need to go to 90° northern latidtude and then back to 17° latitude. This means angle is:
C=2*(90-17)=2*73°=146°
This gives an arc length of:
We can see that flying north is shorter. It is shorter by:
12440.71 miles - 10090.8 miles = 2349.91 miles
Where:
L= arc length (in this problem it is disance we need to travel)
R = radius of circle (in this problem it is equal to a radius of Earth)
C = angle we need to pass
We are told that two cities lie halfway around the world. If we fly to west this means angle is 180°.
This gives an arc length of:
If we want to fly to north we need to go to 90° northern latidtude and then back to 17° latitude. This means angle is:
C=2*(90-17)=2*73°=146°
This gives an arc length of:
We can see that flying north is shorter. It is shorter by:
12440.71 miles - 10090.8 miles = 2349.91 miles
Answer:
The Matlab code along with the plot of slope field for the given differential equation is provided below.
Step-by-step explanation:
Matlab quiver function:
The Matlab's quiver function may be used to plot the slope field lines for any differential equation.
The syntax of the function is given by
quiver(x, y, u, v)
Where matrices x, y, u, and v must all be the same size and contain corresponding position and velocity components.
Matlab Code:
[t,y] = meshgrid(0:0.2:2, 0:0.2:2);
v = sin(y) + sin(t);
u = ones(size(v));
quiver(t,y,u,v)
xlabel('t')
ylabel('y(t)')
xlim([0 2])
ylim([0 2])
Output:
The plot of the given differential equation is attached.
