In what ways do advertisers<span> in </span>magazines use sexual imagery<span> to </span>appeal<span> to </span>youth<span>? </span>One study classified each<span> of </span>1500 full-page<span> or </span>larger ads<span> as "</span>not sexual<span>" or ..</span>
Hello,
Answer D
1) if 4x+2>0 then |4x+2|=4x+2
==> 4x+2<26
==>4x<24
==>x<6
2) if 4x+2<0 then |4x+2|=-(4x+2)=-4x-2
==>-4x-2<26
==>-4x<28
==>x>-7
thus -7<x<6
The sum of the first n terms in a geometric sequence given the first term (a1) and the common ratio (r) is calculated through the equation,
<span>Sn </span>= (<span><span><span>a1</span>(1−<span>r^n</span>) / (</span><span>1−r)
Substituting the known terms,
Sn = (20)(1 - (1/4)^4)) / (1 - 1/4)
Sn = 26.5625
Thus, the sum of the first four terms is 26.5625. </span></span>
Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:
![\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac2n%5Cright%5D%2C%5Cleft%5B%5Cdfrac2n%2C%5Cdfrac4n%5Cright%5D%2C%5Cleft%5B%5Cdfrac4n%2C%5Cdfrac6n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7B2%28n-1%29%7Dn%2C2%5Cright%5D)
Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,
where 
. Each interval has length 
.
At these sampling points, the function takes on values of
We approximate the integral with the Riemann sum:
Recall that
so that the sum reduces to
Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:
Just to check:
So you want to plug in the height for h and solve for t
36 = -16t^2+14t+36
So you get 14/16 which simplifies to
7/8 seconds
Hope this helped!
