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3 years ago

Solve each of the following equations for xx using the same technique as was used in the Opening Exercise.

Mathematics

1 answer:

devlian [24]3 years ago

7 0

Answer:

The solve of this equation is X = 4,06

Step-by-step explanation:

To solve this formula:

2 ( X² - 16) = 1

You must use the distributive law of multiplication, thus:

2X² - (16×2) = 1

2X² - 32 = 1

2X² = 1 + 32

X² = 33/2

X² = 16,5

X = √16,5

X ≈ 4,06

Thus, the solution of this equation is:

I hope it helps!

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Goshia [24]

Answer:

A. The fraction 1 $\frac{1}{6}$ would negative, since she is cutting off/losing hair rather than gaining it.

B. (this is just an improper fraction converted to have the same denominator as the second fraction, and is equivalent to -1 $\frac{1}{6}$ )--> - $\frac{14}{12}$ + $\frac{5}{12}$ = - $\frac{9}{12}$ or - $\frac{3}{4}$

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3 years ago

Find the measure of angle D, and the perimeter and area of parallelogram abcd

Alecsey [184]

Answer:

It is the last choice.

Step-by-step explanation:

m < D = 180 - 28 = 152 degrees ( as same side angle add up to 180 degrees).

The perimeter = 2*17 + 2*25 = 84 cm ( as opposite sides of a parallelogram are congruent).

The area = base * height = 8 * 25

= 200 cm^2.

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3 years ago

Please help i am stuck and trying not to fail lol. also if you can show work pls

wel

Given:

The figure of rectangle.

To find:

a. The diagonal of the rectangle.

b. The area of the rectangle.

c. perimeter of the rectangle.

Solution:

(a)

In a right angle triangle,

$\sin \theta=\dfrac{Perpendicular}{Hypotenuse}$

$\sin 30=\dfrac{12}{Hypotenuse}$

$\dfrac{1}{2}=\dfrac{12}{Hypotenuse}$

$Hypotenuse=12\times 2$

$Hypotenuse=24$

So, the diagonal of the of the rectangle is 24 units.

(b)

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

$\tan 30=\dfrac{12}{Base}$

$\dfrac{1}{\sqrt{3}}=\dfrac{12}{Base}$

$Base=12\sqrt{3}$

Length of the rectangle is 12 and width of the rectangle is $12\sqrt{3}$ . So, the area of the rectangle is:

$Area=length \times width$

$Area=12 \times 12\sqrt{3}$

$Area=144\sqrt{3}$

So, the area of the rectangle is $144\sqrt{3}$ sq. units.

(c)

Perimeter of the rectangle is:

$P=2(length+width)$

$P=2(12+12\sqrt{3})$

$P=24+24\sqrt{3}$

$P\approx 65.57$

Therefore, the perimeter of the rectangle is about 65.57 units.

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3 years ago

Another geometry file upload

bagirrra123 [75]

Cross multiplication 13x -13 = 8x+12
combining like terms 13x -8x =12 +13
5x= 25 x= 5

x=5

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3 years ago

(SAT Prep) Find the value of x

ElenaW [278]

X=25°

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