The minimum number of shirt they will sell to make the given profit is 192 shirts
<h3>Inequality expression</h3>
Inequalities are equations not separated by an equal sign.
If a cheerleading team plans to sell t-shirts as a fundraiser and the teams goal is to make profit of at least $1248 with each t-shirt sold at $6.50, then the equation required is;
6.50t ≥ 1246
Divide both sides by 6.50
6.50t/6.50 ≥1246/6.5
t ≥ 192
Hence the minimum number of shirt they will sell to make the given profit is 192 shirts
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Answer:
Hence the adjusted R-squared value for this model is 0.7205.
Step-by-step explanation:
Given n= sample size=20
Total Sum of square (SST) =1000
Model sum of square(SSR) =750
Residual Sum of Square (SSE)=250
The value of R ^2 for this model is,
R^2 = \frac{SSR}{SST}
R^2 = 750/1000 =0.75
Adjusted 
:
Where k= number of regressors in the model.
Answer:
x = 15
Step-by-step explanation:
2 = -7/4 + 1/4x
+7/4 +7/4 Add 7/4 to both sides
15/4 = 1/4x Divide both sides by 1/4
15 = x
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Check the picture below.
so let's use those two points the line passes through to get its slope.
Answer:
13 units
Step-by-step explanation:
(x₁,y₁) = (-5 , 3) & (x₂ , y₂) = (7 ,8)
![= \sqrt{(7-[-5])^{2}+(8-3)^{2}} \\\\= \sqrt{(7+5)^{2}+(8-3)^{2}} \\\\= \sqrt{(12)^{2}+(5)^{2}}\\\\=\sqrt{144+25}\\\\=\sqrt{169}\\\\= 13](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%287-%5B-5%5D%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B%287%2B5%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%20%5Csqrt%7B%2812%29%5E%7B2%7D%2B%285%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B144%2B25%7D%5C%5C%5C%5C%3D%5Csqrt%7B169%7D%5C%5C%5C%5C%3D%2013)
