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MariettaO [177]
3 years ago
15

DONT CLICK ON THIS ok lol

Mathematics
2 answers:
nasty-shy [4]3 years ago
6 0

Answer:

u told me not to so i did it (its might be B)

Step-by-step explanation:

so i do the did the and the make than the marh and rhe barf and the ract and the rekt

valentinak56 [21]3 years ago
5 0

She can only buy 2 whole packs.

Acording to the graph, 2 whole pakcs will cost $22, and 3 whole packs will cost $33. She can't afford 3 whole packs as we can see as she only has $30.50.

Let me know if you have any questions, thanks!

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A farmer has 24 bushels of apples and can harvest 22 bushels of apples each day?
sweet-ann [11.9K]

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5 0
3 years ago
Given the problem below what mistake did Bob make in solving the equation? Bob and his friends paid $30 for 3 sandwiches and and
storchak [24]

Answer:

Bob forgot to distribute 3 to 1.50 in the parentheses

Step-by-step explanation:

Bob made the mistake in his first step.

In the equation 3(x + 1.50) = 30, the 3 has to be distributed to both x and 1.50.

But, Bob only distributed it to x, which led him to get the wrong answer.

So, Bob's mistake when solving was that he forgot to distribute the 3 to 1.50

7 0
3 years ago
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
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