Answer:
(x+3)(x+4)(x-4)
x+2 and x-3 are not factors but x-4 is
Step-by-step explanation:
let's factor it :)
x^3 + 3x^2 - 16x -48
first we will factor this:
x^3 + 3x^2
x^2(x + 3)
then factor the second part :
- 16x - 48
-16(x + 3)
so now,
x^2(x + 3) - 16(x + 3)
factor out x+3
(x+3)(x^2 - 16)
factor x^2 - 16
(x+3)(x+4)(x-4)
(2B +5A)/7 = (2(-2, -12) +5(-9, 2))/7 = (-4-45, -24+10)/7 = (-7, -2)
Selection B is appropriate.
Answer:
Part 1) 
Part 2) 
Part 3) 
Part 4) 
Part 5) 
Step-by-step explanation:
Part 1) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem

Part 2) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem

Part 3) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem

substitute the values





Part 4) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem

Part 5) we know that
If two triangles are similar
then
the ratio of their corresponding sides are equal
so
In this problem

Answer:
This is a 30-60-90 triangle so you would do this formula:
Short side (opposite the 30 degree angle) = x.
Hypotenuse (opposite the 90 degree angle) = 2x.
Long side (opposite the 60 degree angle) = x√3.
Step-by-step explanation:
F(x)=y=2x+3
P (1,5)
Substitute x and y:
5=2*(1)+3
5=5 true
Point P (1,5) is on the graph of f.