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3 years ago

For the equation 2(4x+10)=8x+k what value of k will create infineltly many solutions please help

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

3 0

Answer:

The value of k = 20 for equation 2(4x+10)=8x+k to have infinitely many solutions.

Step-by-step explanation:

Given the expression

$2(4x+10)=8x+k$

solving

$2(4x+10)=8x+k$

$8x+20 = 8x+k$

We know that the equations with infinitely many solutions have the same expressions on both sides

It means the value of k can be determined by further simplifying such as

$8x+20 = 8x+k$

8x+20-8x = k

20 = k

Therefore, the value of k = 20 for equation 2(4x+10)=8x+k to have infinitely many solutions.

VERIFICATION:

Given

$2(4x+10)=8x+k$

$8x+20 = 8x+k$

Put k = 20 in the equation

$8x+20 = 8x+20$

$8x+20 - 8x+20 = 0$

$0 = 0$

equations with infinitely many solutions have the same expressions on both sides.

This means the statement is always true.

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Answer:

$\begin{gathered} y=\frac{9}{6}x-9 \\ l=\frac{P}{2}-w \end{gathered}$

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$\begin{gathered} a\text{. Solve for y} \\ 6y=9x-54 \\ y=\frac{9}{6}x-\frac{54}{6} \\ y=\frac{9}{6}x-9 \end{gathered}$ $\begin{gathered} b\text{. Solve for l} \\ P=2l+2w \\ 2l=P-2w \\ l=\frac{P}{2}-\frac{2}{2}w \\ l=\frac{P}{2}-w \end{gathered}$

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