Part 1:
Given that the <span>half-life of a radioactive kind of antimony is 60 days. The amount of substance left of a radioactive substance with a half life of </span>

after time t, is given by:

where:

is the original amount of the substance.
Thus, in 240 days, the amount that will be left of the antimony given that the original amount of the antimony is 960 grams is given by:

Part 2:
Given that the half-life of a radioactive kind of tellurium is 70 minutes. The amount of substance left of a radioactive substance with a half life of

after time t, is given by:

where:

is the original amount of the substance.
Thus, in 280 minutes, the amount that will be left of the tellurium given that the original amount of the antimony is 480 grams is given by:

Part 3:
Given that a town's population is currently 10,000. If the population of the town doubles every 38 years, than in 76 years from now, the population of the town must have doubled twice, thus in 76 years from now, the population of the town is given by:
Answer:
1) x > 6
2) x ≥ -21
3) x < 5
4) x < -3
Step-by-step explanation:
I don't know if at school they teach you to graph with parentheses or with dots so I drew both ways
Answer:

Step-by-step explanation:
1.4 is 10 decimal places away from 0.00000000014
The expression that is equivalent to [(4a + 4)/2a] * [a²/(a + 1)] after simplification is; 2a
<h3>How to Simplify Fractions?</h3>
We want to simplify the expression;
[(4a + 4)/2a] * [a²/(a + 1)]
This expression can be further reduced to;
[(4a + 4)/2] * [a/(a + 1)]
Factorizing the numerator to get;
[(4(a + 1)/2] * [a/(a + 1)]
(a + 1) will cancel out to get;
2a
Read more about Simplification of Fractions at; brainly.com/question/26255345
The answer is A, c, e. It is since the one first listed is always on the x- axis and the second is always the y-axis. So u just apply that and u get a, c, and e. The answer is A.C.E.