Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
Step-by-step explanation:
3(2x + 1) - 2(x + 5) - 5(5 - 2x) = 16
6x + 3 - 2x - 10 - 25 + 10x = 16
6x - 2x + 10x = 16 - 3 + 10 + 25
14x = 48
x = 48/14
x = 24/7
Width of the rectangle is 9 units
Step-by-step explanation:
- Step 1: Let the width of the rectangle be x. Then the length = x - 3. Find dimensions of the rectangle if its area = 54 sq. units
Area of the rectangle = length × width
54 = x (x - 3)
54 = x² - 3x
x² - 3x - 54 = 0
x² + 6x - 9x - 54 = 0 (Using Product Sum rule to factorize)
x(x + 6) - 9(x + 6) = 0
(x + 6)(x - 9) = 0
x = -6, 9 (negative value is neglected)
x = 9 units
Surface area of cylinder is given by area of circle + area of the rectangle that curved around the cylinder
Area of the base of the cylinder =

Area of the cylinder 'wall' = width × length =

×

=

×

=

Note that the wall of the cylinder is in the shape of a rectangle. The width of the rectangle is the height of the cylinder. The length of the rectangle is the circumference of the circle base.
Surface area of cone is given by

where

is the slanted height of the cone
SA of cone =

Hence total painted surface area is