Answer:
The C language provides the four basic arithmetic type specifiers char, int, float and double, and the modifiers signed, unsigned, short, and long.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer is:
Conner has located a research source that is sponsored by a pharmaceutical company. Based on the sponsorship, Conner must be careful that the information is not <u>Biased.</u>
<u></u>
When you evaluate and use information from multiple sources, you need to evaluate the information that it must be error-free and not biased and it should be accurate information as you needed.
As in this example, Conner needs to research that the information should not be biased because the information or research source is sponsored by a pharmaceutical company and there is chances of biasedness. So, Conner must be careful that information is not biased.
Three inputs have 8 possible states.
Here they are:
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1
Answer:
public ArrayList onlyBlue(String[] clothes){
ArrayList<String> blueCloths = new ArrayList<>();
for(int i =0; i<clothes.length; i++){
if(clothes[i].equalsIgnoreCase("blue")){
blueCloths.add(clothes[i]);
}
}
return blueCloths;
}
Explanation:
- Create the method to accept an Array object of type String representing colors with a return type of an ArrayList
- Within the method body, create and initialize an Arraylist
- Use a for loop to iterate the Array of cloths.
- Use an if statement within the for loop to check if item equals blue and add to the Arraylist.
- Finally return the arrayList to the caller
