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ankoles [38]
3 years ago
6

3n² + 2n - 8=0 Solve each equation with the quadratic formula

Mathematics
1 answer:
8_murik_8 [283]3 years ago
8 0

Answer:

-2,4/3

Step-by-step explanation:

ax²+bx+c=0

x=\frac{-b \pm\sqrt{b^2-4ac} }{2a} \\3n^2+2n-8=0\\n=\frac{-2\pm\sqrt{2^2-4*3*(-8)} }{2*3} \\n=\frac{-2 \pm \sqrt{4+96}}{6} }\\n=\frac{-2 \pm 10}{6} \\n=\frac{8}{6} =\frac{4}{3}\\or~n=\frac{-12}{6}=-2

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What is the interquartile range?<br> The interquartile range is __
xenn [34]

Answer:

<em>Your IQR or interquartile range is 2.</em>

Step-by-step explanation:

Median: 3

lower quartile: 2

upper quartile: 4

Interquartile range: upper quartile - lower quartile = answer

Interquartile range: 4 - 2 = 2

~hope this helps~

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4 0
3 years ago
Convert the following into metres.<br> A- 22cm<br> B- 180km<br> C-300mm
Alecsey [184]

<em>A) 22cm</em>

<em>(</em><em> </em><em>divide the length value by 100</em><em>)</em>

<em>2</em><em>2</em><em>/</em><em>1</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>

<em><u>=</u></em><em><u>0.22m</u></em>

<em>B</em><em>)</em><em> </em><em>180km</em>

<em>(</em><em> </em><em>multiply the length value by </em><em>1000</em><em>)</em>

<em>1</em><em>8</em><em>0</em><em>×</em><em>+</em><em>1</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>

<em><u>=</u></em><em><u>180000m</u></em>

<em>C</em><em>)</em><em> </em><em>300mm</em>

<em>(</em><em> </em><em>divide the length value by 1000</em><em>)</em>

<em>3</em><em>0</em><em>0</em><em>/</em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>

<em><u>=</u></em><em><u>0.3m</u></em>

<em> </em>

4 0
1 year ago
Read 2 more answers
Can someone help me with these and show the work also?
Snezhnost [94]

QUESTION:

Simplify each expression

ANSWER:

1.) \green{{- 8n}}

2.) \green{{- 2b - 60}}

3.) \green{{- 10x - 14}}

4.) for number 4 study my step-by-step explanation so you can answer that

STEP-BY-STEP EXPLANATION:

1.) First, If the term doesn't have a coefficients, it is considered that the coefficients is 1

WHY?

Learn why:

Why is it considered that the coefficient is 1?

Remember that any term multiplied by \blue{{1}} remains the same :

\blue{{1}} {× x = x}

Step 1:

The equality can be read in the other way as a well, so any term can be written as a product of \blue{{1}} and itself:

{x = } \blue{{1}} {× x}

Step 2:

Usually, we don't need to write multiplacation sign between the coefficient and variable, so the simple form is:

{x = 1x}

This is why we can write the term without the coefficient as a term with coefficient {1}

Now let's go back to solving as what i said if a term doesn't have a coefficient, it is considered that the coefficient is 1

{n - 9n}

\red{{1}} {n -9n}

Second, Collect like terms by subtracting their coefficients

\red{{1n - 9n}}

\red{{( 1 - 9)n}}

Third, Calculate the difference

how?

Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from larger

\red{{1 - 9}}

\red{{- (9 - 1)}}

Subtract the numbers

- (\red{{9 - 1}})n

- \red{{8}}n

\green{\boxed{- 8n}}

2.) First, Distribute - 6 through the parentheses

how?

Multiply each term in the parentheses by - 6

\red{{- 6(b + 10)}}

\red{{- 6b - 6 × 10}}

Multiply the numbers

- {6b} - \red{{6 × 10}}

- {6b} - \red{{60}}

Second, Collect like term

how?

Collect like terms by calculating the sum or difference of their coefficient

\red{{- 6b + 4b}}

\red{{(- 6 + 4)b}}

Calculate the sum

\red{{(- 6 + 4)}}b

\red{{-2}}b

\green{\boxed{- 2b - 60}}

3.) First, Distribute 2 through parentheses

how?

Multiply each term in the parentheses by 2

\red{{2(x - 5)}}

\red{{2x - 2 × 5}}

Multiply the numbers

{2x -} \red{{2 × 5}}

{2x -} \red{{10}}

Second, Distribute - 4 through the parentheses

how?

Multiply each term in the parentheses by - 4

\red{{- 4(3x + 1)}}

\red{{- 4 × 3x - 4}}

Calculate the product

- \red{{4 × 3}}x - 4

- \red{{12}}x - 4

Third, Collect like terms

how?

Collect like terms by subtracting their coefficient

\red{{2x - 12x}}

\red{{(2 - 12)x}}

Calculate the difference

\red{{(2 - 12)}}x

\red{{- 10}}x

Fourth, Calculate the difference

how?

Factor out the negative sign from the expression

\red{{- 10 - 4}}

\red{{- (10 + 4)}}

Add the numbers

- (\red{{10 + 4}})

- \red{{14}}

\green{\boxed{- 10x - 14}}

That's all I know sorry but I hope it helps :)

6 0
2 years ago
Find the volume of the oblique prism
Sergio039 [100]
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8 0
3 years ago
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Ulleksa [173]

Answer:

GRAPH IS IN THE PICTURE BELOW

Step-by-step explanation:

4 0
2 years ago
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