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jasenka [17]
3 years ago
15

What method would you use to square the value 3 + √-1 ? In what other cases would you use this method? Explain.

Mathematics
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

1) the types of number are the negative integers (e.g √-1 √-3 √-5 are not defined)

2) the answer is No, proof:  2x√-1 is not defined because √-1 doesn't exist

3) the answer is No, proof:  √-1 - 3 is not defined because √-1 doesn't exist

4) the answer is Yes, proof: (√-1 )²=  -1 this is a real number

5) the answer is No, proof:  (√-1 )^3=  (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist

6) the result would be defined with the following cases:

   √-1+n,  n>1

    √-1xn,  n<0

    √-1/n,   n<0

7) the result would not be defined with the following cases:

  √-1+n,  n<0

    √-1xn,  n>0

    √-1/n,   n>0

8) to square 3 + √-1, I use the method of complex number

 i²= -1, it implies i= √-1

 so 3+√-1=3+i,  and then (3+√-1)²=(3+i)²= 9 -1+6i= 8-i= 8-√-1

9) it is used for finding complex roots of a number

Step-by-step explanation:

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