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sammy [17]
3 years ago
13

Marking brainliest please help me

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

I think B

Step-by-step explanation:

Not sure but seems like so. Hope I helped U :)

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A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0
2 years ago
What is an equation of the parabola with vertex at the origin and focus (0, 0.75)?
morpeh [17]

Answer:

x^{2} =3y

Step-by-step explanation:

Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form

x^{2} =4py

Because the parameter p is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.

Replacing the parameter value, we have

x^{2} =4(0.75)y\\x^{2} =3y

Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is x^{2} =3y.

8 0
3 years ago
What are 2 answers that can equal 49 in multiplication
jonny [76]
Make a guess and check table to figure out if you do not know it off the top of your head. 

The answer is 7 and 7
5 0
3 years ago
Read 2 more answers
What number needs to be added to both sides of the equation to complete the square?
Doss [256]

Answer:

9/4

Step-by-step explanation:

(-3/2)^2=9/4

6 0
2 years ago
Hi pls help me solve this. Need it now. ​
kenny6666 [7]

Answer:

I Had this question moments ago lol

Step-by-step explanation:

The top one is 52 over 110 and the bottom one is 60 over 65!

3 0
2 years ago
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