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vitfil [10]
3 years ago
10

Are they similar? If so, identify all pairs of congruent angles and proportional sides. Then give the similarity ratio and the s

imilarity statement.​

Mathematics
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

They are similar in shape but not bye mass

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Mr Cole has 30 students in his class. He has twice as many girls than boys. What is the ratio of girla to boys?
Elis [28]

Answer:

12:1/2(3)

Step-by-step explanation: no problem homie

8 0
3 years ago
The Length of a rectangle is 5 centimeters less than twice its width . The perimeter of the rectangle is 80cm. What are the dime
borishaifa [10]
Perimeter is the sum of all a shapes sides.

with that in mind, we know a rectangle has four sides. with 2 pairs being the same.

The length as told is, 5 centimeters less than two times the width. Two times the width would be 2w and five less than that would be minus five. so the length is 2w - 5

now to find the perimeter we do two times the width + two times the length.

2w + 2(2w -5) = 80.
Distribute: 2w + 4w - 10 = 80
Add ten to both sides and combine the 2w & 4w:
6w = 90
Divide both sides by 6: w = 15.

with this we know the width is 15. to find length plug in 15 to the 2w - 5 equation.

2(15) - 5 = 30 - 5 = 25.

Slap on the units and width = 15 cm, length = 25 cm


7 0
3 years ago
15. Which of the following equations was
arlik [135]

Answer:

B

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c (m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 6) and (x₂, y₂ ) = (6, 0)

m = \frac{0-6}{6-0} = \frac{-6}{6} = - 1

Note the line crosses the y- axis at (0, 6 ) ⇒ c = 6

y = - x + 6 or y = 6 - x ⇒ B

3 0
3 years ago
What is the upper and lower bound of 0.82
MrRa [10]

Answer:

What ?

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please help! Will mark brainliest
ser-zykov [4K]

Answer:

Step-by-step explanation:

t1 = a1

t2 = a1 + d

t3 = a1 + 2d

The sum is t1 + t2 + t3 = a1 + a1 + d + a1 + 2d = 3a1 + 3d

Second question

t1 = a1

t2 = a1 + d

t3 = a1 + 2d

t4 = a1 + 3d

...

tn = a1 + (n - 1)*d

Sum = (a1 + a1 + (n- 1)*d) * n / 2

Sum = (2a1 + nd - d) * n / 2

Sum = (2a1*n + n^2*d - nd) / 2

5 0
2 years ago
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