All categories

3 years ago

What is 3-1+12+3 1/5 -2.67

Mathematics

2 answers:

Sidana [21]3 years ago

8 0

If I wrote it right, it should be 14.53

melisa1 [442]3 years ago

7 0

3 1/5 = 3.2 [becaude, 3(5) = 15 + 1 = 16. Next the fraction becomes 16/5, then we divide 16 ÷ 5 which is equal to 3.2. That's why we reversed 3 1/5 to 3.2 ]

So, now the problem becomes ⬇

3 - 1 + 12 + 3.2 - 2.67

So, that means your answer would have to be
14.53

You might be interested in

jose invests money in two simple interests account. he invests twice as much in an account paying 13% as he does in an account p

d1i1m1o1n [39]

Answer:

He invested altogether $900

Step-by-step explanation:

* Lets explain how to solve the problem

- Jose invests money in two simple interests account

- He invests twice as much in an account paying 13% as he does in

an account paying 5%

- That means the amount he invested in the account paying 13% is

twice the amount he invested in the account paying 5%

- He earns $93.00 in interest in one year from both accounts combined

- We need to find how much he invested in each account

- Assume that he invested $x in the account paying 5%

∵ He invested twice as much in an account paying 13% as he does in

an account paying 5%

∴ He invested $2x in the account paying 13%

- The simple interest I = PRT, where P is the money invested, R is the

rate of interest in decimal and t is the time of investment

# Account paying 13%

∵ P = 2x , R = 13/100 = 0.13 , T = 1

∴ I = 2x(0.13)(1)

∴ I = 0.26 x ⇒ (1)

# Account paying 5%

∵ P = x , R = 5/100 = 0.05 , T = 1

∴ I = x(0.05)(1)

∴ I = 0.05 x ⇒ (2)

∵ He earns $93.00 in interest in one year from both accounts

- Add (1) and (2) and equate the sum by 93.00

∴ 0.26 x + 0.05 x = 93.00

- Add like terms in the left hand side

∴ 0.31 x = 93.00

- Divide both sides by 0.31

∴ x = 300

∴ 2x = 2(300)

∴ 2x = 600

∵ x represents the amount of money invested in the account paying 5%

∴ The amount of money invested in the account of 5% is $300

∴ The amount of money invested in the account of 13% is $600

- The total amount of money he invested is the sum of the money

he invested in each account [$300 + $600 = $900]

∴ He invested altogether $900

7 0

3 years ago

Fill in the blank and dropdown menus to form a true statement below.

Pavlova-9 [17]

Answer:

It's polyhedron, not polygon

Because above figure has merely 10 sides.

so the polyhedron above has 10 sides, each of them has 20°.

so total degree in polyhedron is > 180(n-2)

>180(10-2)

> 180×8

> 1440

Step-by-step explanation:

Hope it helps you

5 0

3 years ago

Paul deposited $95,000 in a savings account that pays 4% interest compounded daily. What is his balance at the end of six months

Arada [10]

Answer:

$\$96,919.02$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=6/12=0.5\ years\\ P=\$95,000\\ r=4\%=4/100=0.04\\n=365$

substitute in the formula above

$A=95,000(1+\frac{0.04}{365})^{365*0.5}$

$A=95,000(1+\frac{0.04}{365})^{182.5}=\$96,919.02$

5 0

4 years ago

The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti

DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

$P(t)=10000(0.2)^t$

1) $P(0)$ is the population initially.

$P(1)$ is the population after a year.

$\frac{P(1)}{P(0)}$ represents the population increase factor.

So let's evaluate that fraction:

$\frac{P(1)}{P(0)}$

$\frac{10000(0.2)^1}{10000(0.2)^0}$

$\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2$

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

$P(t)=10000(0.2)^{t}$

We want t to represent months.

A full year is 12 months, in a full year we have that $P(1)=10000(0.2)^1=10000(0.2)=2000$

So we want a new P such that $P(12)=2000$ since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) $P(12)=10000(0.87449)^{12}=2000 \text{approximately}$

b) $P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}$

c) $P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}$

d) $P(12)=10000(0.87449)^{12+12}=400 \text{approximately}$

So a is the function we want.

Also another way to look at this:

$P(t)=10000(.2)^t$ where $t$ is in years.

$P(t)=10000(.2^\frac{1}{12})^t$ where $t$ is in months.

And $.2^\frac{1}{12}=0.874485 \text{approximately}$

8 0

4 years ago

The graph of f(x) = |x| is transformed to g(x) = |x + 1| – 7. On which interval is the function decreasing?

timofeeve [1]

Answer:

g is decreasing for all x less than or equal to -1

Step-by-step explanation:

The graph of the function y = |x| looks like a "vee."

g(x) = |x + 1| - 7 moves that graph 1 unit to the left (I know, it looks backwards!) and down 7 units. See attached image.

Function g(x) is decreasing for all $x \le -1$ .

5 0

3 years ago

Read 2 more answers