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Naddika [18.5K]
2 years ago
8

Lee is forming kickball teams that include all of the students who signed up from two schools. Each team must have the same numb

er of players and be from the same school. What is the greatest number of players Lee can put on each team?
Mathematics
1 answer:
tester [92]2 years ago
8 0

Answer:

The answer is (12 players)

Step-by-step explanation:

2 x 2 x 3 = 12      

36 - 12 = 24

You might be interested in
Find the measure of <6
eduard

Answer:

110 degrees

Step-by-step explanation:

Parallels lines, when intersected by a straight line, form congruent angles. Therefore 110 is equal to angle 6

4 0
2 years ago
Rozalie spent $26 at a parking garage in downtown Orlando. The garage charged a base free of $7.50 for the first hour and a hour
bagirrra123 [75]
ANSWER : Rozalie spent 6.73 hours at the garage


rate of change = $2.75
base fee = $7.50

set up your equation:
2.75h + 7.5 = 26
($2.75/hour plus the base fee of $7.50 equals the total amount spent, $26)

Now just solve for h

2.75h + 7.5 = 26
2.75h = 18.5
h = 6.727273 (rounded)
h = 6.73

So the answer would be Rozalie spent about 6.73 hours at the garage.

6 0
2 years ago
Fill in the blank spaces please.
Kisachek [45]

<u><em>PART A</em></u>

If 4 pounds = 10 dollars...

4/2 = 2

10/2 = 5

<u>So for 2 pounds, it would cost </u><u>$5.00</u>

Now for the 1 pound one

4/1 = 4

10/4 = 2.5

<u>For the 1 pound one, it would cost </u><u>$2.50</u>

<u></u>

<u><em>PART B</em></u>

We know that 4 pounds = 10 bucks

Since 1 is 1/10 of 10 (in the cost section), we have to apply this to the pounds section. 4/10 = 0.4. Therefore, <u>$1 = 0.4lb</u>

Now for the last blank...

Since $1 = 0.4, we multiply that by 9. 0.4 x <u>$9 = 3.6lb</u>

<u></u>

<em>HOPE THIS HELPED</em>

5 0
2 years ago
An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the
sdas [7]

Answer:

a

    n=  75, 582

b

  n=    2300

c

  n =   253

Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

                             n=    2300

   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
3 years ago
A 32cm long string just fits round the perimeter of a square board. The area of the board is
Ierofanga [76]

Answer:

64cm2

Step-by-step explanation:

(32÷4)=8

8×8=64cm2

8 0
3 years ago
Read 2 more answers
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