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Katena32 [7]
3 years ago
14

sin alpha = 7/25, alpha lies in quadrant ii, and cos beta = 2/5, beta lies in quadrant i. find cos(alpha-beta).

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

Therefore \cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}

Step-by-step explanation:

Given values are

\sin \alpha=\frac{7}{25}

\cos \beta=\frac{2}{5}

\sin^2x+\cos^2=1

\cos \alpha=\sqrt{1-\sin^2\alpha}

\cos \alpha=\sqrt{1-(\frac{7}{25})^2}

\cos \alpha=\sqrt{1-\frac{49}{625}}

\cos \alpha=\sqrt{\frac{576}{625}}

\cos \alpha=\frac{24}{25}

\sin \beta=\sqrt{1-\cos^2\beta}

\sin \beta=\sqrt{1-(\frac{2}{5})^2}

\sin \beta=\sqrt{1-\frac{4}{25}}

\sin \beta=\frac{\sqrt{21}}{5}

\cos(\alpha-\beta)=\cos\alpha\cos\beta+\sin\alpha\sin\beta

\cos(\alpha-\beta)=\frac{24}{25}\times\frac{2}{5}+\frac{7}{25}\times\frac{\sqrt{21}}{5}

\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}

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