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3 years ago

What's the correct formula for this function?

Mathematics

2 answers:

Reptile [31]3 years ago

8 0

Answer:

Option C. y = -2x + 3

Step-by-step explanation:

When we look at this function we see that it has a negative slope and the y-intercept is equal to (0,3). From this we know that the function we are looking for will be looking like...

y = mx + 3

And as I said earlier since the slope is negative, the only right option is this case will be Option C

RUDIKE [14]3 years ago

5 0

Answer:

The correct anwer is (C) : y = - 2x + 3

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Max spent $53 and now has no money left. He had $ before his purchase.

Yuri [45]

Can you restate it or rewrite it? It doesn't have enough for me to answer this.

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3 years ago

If log10 y = 2. what does y equal?

lys-0071 [83]

Answer:

$log_{10} (100) = 2$

Step-by-step explanation:

Here, the given expression is:

$log_{10} (y) = 2$

Now, by logarithm rules, we know

if $log_{b}(x) = z$

, then x = $b^{z}$

Comparing here, b = 10 and z = 2

⇒ y = $10^{2} = 100$

or, $log_{10} (100) = 2$

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3 years ago

Select the best description of exponential equation

serious [3.7K]

the answer is -a .

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2 years ago

The function g(x) = 12,500(0.91)x represents the value of a piece of farm equipment after x years. Approximately when will its v

topjm [15]

Answer:

B. 7.3 years

Step-by-step explanation:

The question is wrong. The correct function is :

$g(x)=12500(0.91)^{x}$

We have the function $g(x)$ that represents the value of a piece of farm equipment after $x$ years.

This means that when $x=0$ its original value is :

$g(0)=12500(0.91)^{0}=12500$

Now we want to calculate approximately when will its value be half its original value. Then, we write :

$\frac{12500}{2}=6250$

$6250$ is half of its original value. We need to find $x$ that satisfies the following equation :

$g(x)=6250=12500(0.91)^{x}$

Solving for $x$ :

$6250=12500(0.91)^{x}$ ⇒

$0.5=(0.91)^{x}$

Now we apply natural logarithm to each side of the equation :

$ln(0.5)=ln[(0.91)^{x}]$

Using logarithm properties :

$ln(0.5)=ln[(0.91)^{x}]$ ⇒

$ln(0.5)=x[ln(0.91)]$

$x=\frac{ln(0.5)}{ln(0.91)}$ ⇒

$x$ ≅ $7.3496$

The correct option is B. 7.3 years

4 0

3 years ago

an item initially valued at 100$ goes down in value by 20% the first year then goes up in value 10% the second year and goes dow

Fed [463]

$100 * 0.2 = $20.
$100 - $20 = $80.
$80 * 0.1 = $8.
$80 + $8 = $88.
$88 * 0.2 = $17.60
$88 - $17.60 = $70.40.
Answer: $70.40

8 0

3 years ago

What's the correct formula for this function? ​

What's the correct formula for this function?