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sineoko [7]
3 years ago
15

X= e^t -9 , y= e^2t Find the cartesian equation

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0
\bf \begin{cases}
x=e^t-9\\\\
y=e^{2t}
\end{cases}\\\\
-----------------------------\\\\
x=e^t-9\implies x+9=e^t\implies ln(x+9)=ln(e^t)
\\\\\\
ln(x+9)=\underline{t}\\\\
-----------------------------\\\\
y=e^{2t}\iff y=e^{2\underline{ln(x+9)}}
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If quadrilateral MNPO is reflected over the x-axis, what are the coordinates of
jenyasd209 [6]

<em>Note: you have not added the image, so I am assuming the quadrilateral MNOP with coordinates M(-4, 0), N(5, -3), P(2, 6) and O(-5, 7). It will anyhow clear your concept as I would explain the concept of reflection over the x-axis.</em>

Step-by-step explanation:

Considering the quadrilateral MNPO with assumed vertices

  • <em>M(-4, 0)</em>
  • <em>N(5, -3)</em>
  • <em>P(2, 6)</em>
  • <em>O(-5, 7)</em>

<em />

<em>THE RULE OF REFLECTION </em>states that when we tend to reflect a point let say (x, y), across the x-axis, the x-coordinate does not change or transform, but the y-coordinate is changed into its opposite sign i.e. (x,-y).

So, the coordinates of the point in the image after quadrilateral MNPO is reflected over the x-axis will be:

<h3>(x, y)                      (x, -y)</h3>

<em>M(-4, 0)                     M'(-4, 0)</em>

<em>N(5, -3)                     N'(5, 3)</em>

<em>P(2, 6)                      P'(2, -6)</em>

<em>O(-5, 7)                   O'(-5, -7)</em>

Hope, it will help you clear your concept regarding reflection of an object over the x-axis. Using this understanding, you can solve any other question related to this topic.

6 0
4 years ago
Gerry has two different part-time jobs, and he had work 20 hours per week at each job. He earns $8 per hour at one job. Which ex
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