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Arte-miy333 [17]
3 years ago
7

Gerry has two different part-time jobs, and he had work 20 hours per week at each job. He earns $8 per hour at one job. Which ex

pression represents how much Gerry earned last week if he earns d dollars per hour at this other job? A- 20+20d B- 160+ 20d C- 40+ d D- 160+ 8d PLZZZZZZ ANSWER THX!!!!!!
Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:The answer is B. 160 + 20d

Step-by-step explanation: first find out the total for how much he makes at the first job. 20 x 8 = 160 then you just write out the equation

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sheila works for a fishing companyshe is paid $20 per day and an additional $2 fo ea lobster she catches. she wats to know how m
kari74 [83]
5 days x $20 payment each day=$100
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5 0
3 years ago
Evaluate each expression.<br> (-4 - 3) ÷ (-8 + 2 - 8 + 7)
anzhelika [568]

Answer:

(-4 - 3) ÷ (-8 + 2 - 8 + 7) = 1

Step-by-step explanation:

(-4 - 3) ÷ (-8 + 2 - 8 + 7)

= -7  ÷ -7

= 1

3 0
3 years ago
Factor the four-term polynomial.<br> pq - 2r + pr-29
vredina [299]

Your answer should be -18?

3 0
3 years ago
A random sample of 20 healthy adults was collected and their body temperatures were measured in degrees Fahrenheit. The data can
castortr0y [4]

Answer:

Step-by-step explanation:

Hello!

You need to test the hypothesis that "the average temperature for healthy adults is not equal to 98.6"

The variable of interest is

X: The body temperature of a healthy adult. (Fahrenheit)

And the parameter of interest is the population mean, μ.

The statistic hypotheses are:

H₀: μ = 98.6

H₁: μ ≠ 98.6

α:0.05

Assuming that the variable has a normal distribution you have to use a one-sample t-statistic for this test.

Attached to the answer is the data of body temperature of n=19 healthy adults. Since you didn't copy the raw data for your exercise I'll use this to answer the question.

Using the data the sample mean and standard deviation are:

X[bar]= 98.12

S= 0.69

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~~t_{n-1}

t_{H_0}= \frac{98.12-98.6}{\frac{0.69}{\sqrt{19} } } = -3.03

This test is two-tailed, using the critical value approach, you have the rejection region divided into two tails determined by two critical values:

t_{n-1;\alpha /2}= t_{18;0.025}= -1.965

t_{n-1;1-\alpha /2}= t_{18;0.975}= 1.965

Decision rule:

If t_{H_0} ≤ -1.965 or if t_{H_0} ≥ 1.965, the decision is to reject the null hypothesis.

If -1.965 < t_{H_0} < 1.965, the decision is to not reject the null hypothesis.

The calculated statistic is less than the lower critical value, the decision is to reject the null hypothesis.

Using a significance level of 5%, there is enough evidence to reject the null hypothesis. Then you can conclude that the true mean body temperature for healthy adults is not equal to the traditional 98.6F.

I hope this helps!

7 0
4 years ago
I’ll mark Brainiest?
Usimov [2.4K]
The answer is D. Group =2
8 0
3 years ago
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