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3 years ago

Help me plz someone??

Mathematics

1 answer:

svetlana [45]3 years ago

7 0

Answer:

200π m²

Step-by-step explanation:

The lateral area (A) of a cone is calculated as

A = πrl ( r is the base radius and l the slant height )

Here r = 8 and l = 25, then

A = π × 8 × 25 = 200π cm²

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Write a system of equations, with 1 equation describing the cost to bowl at Bowl-O-Rama and the other describing the cost to bow

skad [1K]

Bowl-O-Rama:

y = 2 + 2.50x

Bowling Pinz:

y = 4 + 2x

When you graph this, the solution is (4, 12).

This represents that when you play 4 games for either company, both the prices will be the same, $12.

6 0

4 years ago

The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line? 1. y = -2x + 6

densk [106]

Answer:

The Answer is: y = 1/3x - 2

Step-by-step explanation:

Giving points: (0, -2) and (6, 0).

First find the slope:

m = y - y1/(x - x1)

m = -2 - 0/0 - 6

m = -2/-6 = 1/3

Use the point slope form of the equation with point (0, -2) and solve for y:

y - y1 = m(x - x1)

y - (-2) = 1/3(x - 0)

y + 2 = 1/3x

y = 1/3x - 2

Hope this helps! Have an Awesome day!! :-)

8 0

4 years ago

For your vegetable garden, you plan to plant 5 12 of it in corn, 1 6 in different kinds of beans, and 1 12 in tomatoes. You will

Ymorist [56]

Answer:

$\frac{2}{9}$ part of the garden will be planted in onions and squash combined.

Step-by-step explanation:

Given:

For your vegetable garden, you plan to plant 5 12 of it in corn, 1 6 in different kinds of beans, and 1 12 in tomatoes.

You will plant the remainder equally in eggplant, onions, and squash.

Now, to find the part of garden that will be planted in onions and squash combined.

Part of garden plan for planting corn = $\frac{5}{12}$

Part of garden plan for planting kinds of bean = $\frac{1}{6}$

Part of garden plan for planting tomatoes = $\frac{1}{12}$

So, adding all the parts of corn, beans and tomatoes:

$\frac{5}{12}+\frac{1}{6} +\frac{1}{12} \\\\=\frac{5+2+1}{12} \\\\=\frac{8}{12}$

Now, to get the rest of the parts of garden use to plant eggplant, onions, and squash we subtract $\frac{8}{12}$ from 1 whole:

$1-\frac{8}{12} \\\\=\frac{12-8}{12} \\\\=\frac{4}{12}$

As, given planting the remainder equally in eggplant, onions, and squash.

So, each will be planted in part of:

$\frac{4}{12} \div 3$

$=\frac{4}{12}\times \frac{1}{3}$

$=\frac{4}{36}$

On simplifying it:

$=\frac{1}{9}$ .

Thus, $\frac{1}{9}$ part of the garden for each eggplant, onions, and squash.

Now, to get the part of the garden will be planted in onions and squash combined we add $\frac{1}{9}$ part of garden planting for onions and $\frac{1}{9}$ of squash:

$\frac{1}{9} +\frac{1}{9} \\\\=\frac{1+1}{9} \\\\=\frac{2}{9}$