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Svet_ta [14]
4 years ago
15

Cual es el decimal de -2/6

Mathematics
1 answer:
Andru [333]4 years ago
4 0

Answer:

- 0.333  

(repitiendo)

Step-by-step explanation:

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Sales at an airport shop has increased by 25 transactions to a total of 400 transactions per day. What is the increased transact
Zielflug [23.3K]

Answer:

6.66

Step-by-step explanation:

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3 years ago
If y=28 when x=168, find y when x=108.
Softa [21]

Answer:

y=18

Step-by-step explanation:

168/28=6

108/6=18

y=18

8 0
4 years ago
Read 2 more answers
What expression is equivalent to -1/3(6x+15)-3
Anna11 [10]

Answer:

\large\boxed{-\dfrac{1}{3}(6x+15)-3=-2x-8}

Step-by-step explanation:

-\dfrac{1}{3}(6x+15)-3\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=\left(-\dfrac{1}{3}\right)(6x)+\left(-\dfrac{1}{3}\right)(15)-3\\\\=-2x-5-3\\\\=-2x-8

5 0
4 years ago
A bird species in danger of extinction has a population that is decreasing exponentially (A = A0e^kt). Five years ago, the popul
Natalija [7]

Answer:

It'll take approximately 34 years from today.

Step-by-step explanation:

in order to solve this problem we first need to find the rate of change, "k", to do that we will use the given information where the population was 1400 five years ago and its now 1000. Applying this data to the equation gives us:

A = A_0*e^{k*t}\\1000 = 1400*e^{5*k}\\1400*e^{5*k} = 1000\\e^{5*k} = \frac{1000}{1400}\\ln(e^{5*k}) = ln(\frac{1000}{1400})\\5*k = ln(1000) - ln(1400) \\k = \frac{ln(1000) - ln(1400)}{5} = -0.06729

We now know the value for "k", we can estimate how many years it will take for the bird population to dip below 100. We have:

100 = 1000*e^{-0.06729*t}\\e^{-0.06729*t} = \frac{100}{1000}\\ln(e^{-0.06729*t} = \frac{1}{10}\\-0.06729*t = ln(0.1)\\t = -\frac{ln(0.1)}{0.06729} = 34.22

It'll take approximately 34 years from today.

8 0
4 years ago
The freefall function to calculate velocity, v, of an object that begins at rest and falls for distance d is v(d) = 2gd , where
andrey2020 [161]

9514 1404 393

Answer:

  32.8 m/s

Step-by-step explanation:

The function is actually ...

  v(d) = \sqrt{2gd}

Filling in the given values, the velocity is about ...

  v(55) = \sqrt{2\cdot9.8\cdot55}=\sqrt{1078}\approx32.8\text{ m/s}

The velocity at the end of the free-fall is about 32.8 meters per second.

3 0
3 years ago
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