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Sergio [31]
2 years ago
5

What is 6 over x-8 - 3x over x squared -5

Mathematics
1 answer:
Burka [1]2 years ago
4 0

Answer:

6/x^5-2x-8

Step-by-step explanation:

6 over x-8-3x is

6/x-8-3x/x^-5

Over x^-5

x^-5 can be rewritten as

6/x-8-3x+x^5

Simplify:

6/x^5-2x-8

Hope this helps!

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Tom has a solid, wooden block that is a rectangular prism with non-square bases. He saws the prism parallel to the base. What sh
Katyanochek1 [597]

Answer:

A) Rectangle

Step-by-step explanation:

Hope this helps :D

6 0
3 years ago
The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area aff
Karolina [17]

The correct statement about the earthquake in the state is option c. State A had approximately 3,362 more earthquakes than State B.

<h3>How to solve for the earthquake in the state A</h3>

we have x/y = 0.00299

y = 163696

To solve for x we have

163696 * 0.00299

= 4895 earthquakes

<h3>Next we have to solve for earth quakes in state B</h3>

x = 0.1402 x 10931

= 1533

Next we have to find the difference

4895 - 1533 = 3362 earthquakes.

We have to conclude that state A has 3362 earthquakes more than B. Hence the answer is c.

<h3 />

Read more on seismic activity here:

brainly.com/question/13017813?referrer=searchResults

#SPJ1

Complete question

The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area affected. The table shows the land area and seismic activity density.

Which statement about the number of earthquakes the states had for the given time span is true?

State A had approximately 1,533 more earthquakes than State B.

State B had approximately 1,533 more earthquakes than State A.

State A had approximately 3,362 more earthquakes than State B.

State B had approximately 3,362 more earthquakes than State A.

8 0
1 year ago
Need help fast please thanks
murzikaleks [220]

Answer:

c = 41 ft

Step-by-step explanation:

To solve this problem, we can use the pythagorean theorem, which is defined by the formula a^2+b^2=c^2. We are given both the lengths of the legs, so all we need to do is to plug them both in and solve for c:

9^2+40^2 = c^2\\c^2 = 81 + 1600\\c^2 = 1681\\c = 41

This is the first option.

8 0
3 years ago
Help.... Other question got deleted.
Helen [10]
-2/25 is the slope
x1=4
hope this helps!
7 0
3 years ago
Find the sum of ∠BCD and ∠SBT in terms of x.
AleksAgata [21]
Let's\ \angle TCB=y^o\\\\\angle SBT\ is\ the\ exterior\ angle\ of\ \Delta TCB,\ therefore\ |\angle SBT|=x^o+y^o.\\\\|\angle\ BCD|\ +\ y^o=180^o-angles\ on\ one\ side\ of\ a\ straight\ line\\\\|\angle BCD|=180^o-y^o\\\\therefor\\\\\angle SBT+\angle BCD=x^o+y^o+180^o-y^o=x^o+180^o\\\\\boxed{Answer:\angle SBT+\angle BCD=x^o+180^o}
4 0
3 years ago
Read 2 more answers
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