1 year ago

What is 6 over x-8 - 3x over x squared -5

Mathematics

1 answer:

Burka [1]1 year ago

4 0

Answer:

6/x^5-2x-8

Step-by-step explanation:

6 over x-8-3x is

6/x-8-3x/x^-5

Over x^-5

x^-5 can be rewritten as

6/x-8-3x+x^5

Simplify:

6/x^5-2x-8

Hope this helps!

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit

Kobotan [32]

Answer:

2 $\sqrt{5}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplifying the radicals

$\sqrt{125}$ = $\sqrt{25(5)}$ = $\sqrt{25}$ × $\sqrt{5}$ = 5 $\sqrt{5}$

$\sqrt{180}$ = $\sqrt{36(5)}$ = $\sqrt{36}$ × $\sqrt{5}$ = 6 $\sqrt{5}$

$\sqrt{45}$ = $\sqrt{9(5)}$ = $\sqrt{9}$ × $\sqrt{5}$ = 3 $\sqrt{5}$

Thus

$\sqrt{125}$ - $\sqrt{180}$ + $\sqrt{45}$

= 5 $\sqrt{5}$ - 6 $\sqrt{5}$ + 3 $\sqrt{5}$

= 2 $\sqrt{5}$

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2 years ago

What is the LCM of 10 and 14

Oduvanchick [21]

The LCM of 10 and 14 is 2.

5 0

2 years ago

Read 2 more answers

Write the absolute value inequality in the form |x-b| c that has the solution set x<-5 or x>7.

Daniel [21]

Answer:
|x - 1| > 6
Step-by-step explanation:
b is the centre:
(-5 + 7)/2
2/2 = 1
b = 1
c is the distance from the centre
c = 7 - 1 = 6
Since it's an or case, > with the modulus
|x - 1| > 6

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saw5 [17]

Answer:

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Step-by-step explanation:

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