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lidiya [134]
4 years ago
15

Emma is counting by sixes what # will she say

Mathematics
2 answers:
MariettaO [177]4 years ago
8 0
6 12 18 24 30 36 42 48 
Arlecino [84]4 years ago
7 0
6 ,12 ,18, 24, 30 ,36 ,42, 48,

She will keep adding by 6
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In class A, 17 students in a class of 25 passed an exam. In class B, 13 out of 20 passed. In class C, 7 out of 10 passed. Which
Sergio [31]

Answer:

class C

Step-by-step explanation:

a=(17/25)=0.68

b=(13/20)=0.65

c=(7/10)=0.7

5 0
3 years ago
Jessica records the number of winners at the Dunk-a-Teacher booth at the town fair as shown in the table. If there are 750 conte
Keith_Richards [23]

Between 75 and 98.

Step-by-step explanation:

Let's first have a look at the previous data available:

Friday, 27 dunk teachers out of 215 participants (12.5%)

Saturday: 54 dunk teachers out of 417 participants (12.9%)

Sunday: 39 dunk teachers out of 368 participants (10.6%)

So, based on the previous 3 days, she can expect between 10% and 13% will dunk a teacher.

If she has 750 contestants on Monday, the number of winners should then be in the range of 75 (10% of 750) and 98 (13% of 750).

8 0
3 years ago
If ∆GFE ~ ∆CBE, find the value of x
saw5 [17]
2/5 x 60 = 24
2/5 x (4x - 1) = x+5
8x - 2 = 5x + 25
3x = 27
x = 9
The value of x is 9
4 0
3 years ago
Read 2 more answers
7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many
BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>
5 0
3 years ago
The perimeter of a rectangular field is 292 yards. If the width of the field is 63 yards, what is its length?
Feliz [49]

Answer:

83

Step-by-step explanation:

do the math

5 0
3 years ago
Read 2 more answers
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