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MAVERICK [17]
3 years ago
7

When analyzing related data variables, how can one tell which one is the independent variable and which one is the dependent var

iable?
Mathematics
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

Dependent and independent Variable.

Step-by-step explanation:

Dependent and independent Variable.

  • The two variables in an experiment are independent and dependent variable.  
  • Usually, the dependent variable is denoted by y and the independent variable a re denoted by x_i
  • The dependent variable depends on independent variable in an experiment and thus cannot be controlled.
  • On the other hand we can change or control the independent variables to test effect on dependent variable.
  • As the independent variable are changed, we observe corresponding changes in the dependent variable.
  • Example: Let money spend be the dependent variable. It depends on an independent variable of shopping. We may control or change or shopping habits to see the changes in the money spent. Money spent totally depends in the amount f shopping done.
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marla has 4.55 in dimes and quarters. if she ha s7 more quarters than dimes, how many quarters doe she have?
Jlenok [28]

Answer:

number of dimes is 8

number of quarters is 15

Step-by-step explanation:

let 'd' = number of dimes

let 'd+7' = number of quarters

.10d + .25(d + 7) = 4.55

.10d + .25d + 1.75 = 4.55

.35d = 2.80

d = 8

q = 7 + 8

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2 years ago
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Look at the diagram. If RS= 8y + 4, ST = 4y + 8, and RT = 36, find the value of y.
vladimir2022 [97]
<span>RS= 8y + 4, ST = 4y + 8, and RT = 36

RS + ST = RT
</span>8y + 4 + 4y + 8 = 36
12y + 12 = 36
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answer
y = 2 (first choice)
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3 years ago
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Choose the pair of numbers that is not a solution to the given equation.
balandron [24]

Answer:

The pair (0,3) is not a solution to the equation

Step-by-step explanation:

This can be proved by simply replacing the x and y variables in the equation by the x and y values of the pair, and checking if the equation renders a true statement:

By replacing x and y with their values in the pair (0,3), that is x=0 and y=3, in the equation y = 5 - 2x  we get:

3 = 5 - 2 (0)

3 = 5 - 0

3 = 5

which is NOT a true statement.

On the other hand, the other two pairs (2,1) and (1,3) render true statements:

1 = 5 - 2 (2)

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and

3 = 5 - 2 (1)

3 = 5 - 2

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4+10 in distributive law
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