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yuradex [85]
3 years ago
8

Has the marrying age of a man changed over the years? The United States Bureau of the Census takes a formal count of everyone in

the U.S. every 10 years and has provided the following data that gives the median age of an American man at the time of his first marriage.. . Year1910192019301940195019601970198019902000. Median Age25.124.624.324.322.822.823.224.726.126.8. . . . Determine a ten-year period when the average rate of change is negative.a.1910 - 1920. b.1920 - 1930. c.1940 - 1950. d.All of the above
Mathematics
2 answers:
ANTONII [103]3 years ago
8 0
We are given with the data revealing about the median age of an American man marries for the first time in a specific year. In this case, we are asked to determine the average rate of change during a ten-year interval. To have a negative average rate of change, the proceeding decade's median age should be less than the number before. In this case, all of the choices lead to negative average rate of change.
stellarik [79]3 years ago
6 0

Answer: The answer is D: all of the above

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Step-by-step explanation:

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Daniel has a set off green,blue, and red the red marblesmmake up exactly 1halfs of the set the set has 2 blue marble the number
Blizzard [7]

Answer:

There are <u>12 marbles</u> in Daniel's set.

Step-by-step explanation:

Given:

Daniel has a set off green,blue and red.

The red marbles make up exactly half of the set.

The set has 2 blue marbles.

The green marbles in set are as twice of the blue marbles in set.

Now, to find the number of marbles in Daniel's set.

Let the number of marbles in Daniel set be x.

So, the red marbles =  \frac{1}{2}\ of\  x =\frac{x}{2}

Blue marbles = 2.

And the green marbles = 2\times 2 =4.

According to question:

x=\frac{x}{2} +2+4

x=\frac{x}{2} +6

x=\frac{x+12}{2}

<em>Multiplying both sides by 2 we get:</em>

<em />2x=x+12<em />

<em>Subtracting both sides by </em>x<em> we get:</em>

x=12.

Therefore, there are 12 marbles in Daniel's set.

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The composition of any function, f(x), and its inverse, f'(x),
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x

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