Question

If the equation of a circle is (x - 2)2 + (y - 6)2 = 4, it passes through point ______.

Answer 1

Answer:

$(4,6),(2,8),(0,6),(2,4)$ (the list goes on)

Step-by-step explanation:

So the equation

$(x - 2)^2 + (y - 6)^2 = 4$

Let's try to graph it out (I won't actually graph it out here as I can't but try to follow along)

The first thing we notice from the equations is that the circle has a radius of 2, so draw a circle from the origin that has a radius of two, our most notible points at this stage are

$(2,0),(0,2),(-2,0),(0,-2)$

Now applying the transformation of 2 to the right and six up the new points become

$(4,6),(2,8),(0,6),(2,4)$