Answer:
Explanation:
A subdomain is really important on the internet, we can categorize our blog, e-commerce or simple informative website, for example, if we want to have a blog and e.commerce of the same topic, we can have a subdomain for each website, if we separate our website, and we administrate our content is a good signal for SEO, we could have more promotion in search engine.
Answer:
The answer to the give question as follows:
1) \n
2) \t
3) \'
4) \"
5) \\
Explanation:
The description of the above symbols as follows:
- The \n is used to provide the new line spacing.
- The \t is used to provide a tab space.
- To assign a single character value we use \' single.
- The double \" quote is used to assign a string value.
- The backslash is used to provide the character of the escape and it also used in a file path.
I believe the answer is modem
Answer:
Usually good and evil are depicted as black and white or red and white. White being good, or pure.
Explanation:
Answer:
Option d) B is 1.33 times faster than A
Given:
Clock time, 

No. of cycles per instructions, 

Solution:
Let I be the no. of instructions for the program.
CPU clock cycle,
= 2.0 I
CPU clock cycle,
= 1.0 I
Now,
CPU time for each can be calculated as:
CPU time, T = 


Thus B is faster than A
Now,


Performance of B is 1.33 times that of A