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Genrish500 [490]
3 years ago
10

A) How can jitter be reduced on a user’s PC if there is jitter in incoming packets?

Computers and Technology
1 answer:
ELEN [110]3 years ago
6 0

Answer:

a.) Incoming packets can be placed in the buffer and played back without the jitter.

b.) Buffering would increase the latency because there would be a delay in time when the packets enter the buffer and the time is released.

Explanation:

Jitter is referred technically as a packet delay variations.

It is variation in the periodicity of periodic events or a signal from target or the true frequency.

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(1) Prompt the user for a string that contains two strings separated by a comma. (1 pt) Examples of strings that can be accepted
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Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#define MAX_LIMIT 50

int checkComma(char *input)

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int flag = 0;

for(int i = 0; i < strlen(input); i++)

{

if(input[i] == ',')

{

flag = 1;

break;

}

}

return flag;

}

int main(void)

{

char input[MAX_LIMIT];

char *words[2];

char delim[] = ", ";

printf("\n");

do

{

printf("Enter input string: ");

fgets(input, MAX_LIMIT, stdin);

size_t ln = strlen(input) - 1;

if (*input && input[ln] == '\n')

input[ln] = '\0';

if(strcmp(input, "q") == 0)

{

printf("Thank you...Exiting\n\n");

exit(1);

}

else

{

if(checkComma(input) == 0)

{

printf("No comma in string.\n\n");

}

else

{

char *ptr = strtok(input, delim);

int count = 0;

while(ptr != NULL)

{

words[count++] = ptr;

ptr = strtok(NULL, delim);

}

printf("First word: %s\n", words[0]);

printf("Second word: %s\n\n", words[1]);

}

}

}while(strcmp(input, "q") != 0);

return 0;

}

Kindly check the attached image below for the output.

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