All categories

4 years ago

The area of a triangle is 32

1 answer:

7 0

We have the formula A = (h x b) / 2, where A is the area of the triangle, h is the height of the triangle, b is the base of the triangle;
So, 32 =(8 x b) / 2;
Then, 64 = 8 x b;
b = 64 ÷ 8;
b = 8 inches;

You might be interested in

HELPPPPPP PLSSSSSS!!!!!!!!!!

elena-s [515]

Answer:

the answer is 8cm , its shows on ur paper.

5 0

3 years ago

Read 2 more answers

Guys can you help me answer this?

Gelneren [198K]

I can’t see nothing it to white don’t let me Click

6 0

3 years ago

What is the equation for a slope -1 through the point (2,0)?

RUDIKE [14]

Answer:

y = - x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 1, thus

y = - x + c ← is the partial equation

To find c substitute (2, 0) into the partial equation

0 = - 2 + c ⇒ c = 0 + 2 = 2

y = - x + 2 ← equation of line

4 0

3 years ago

What is the repulsive force between two pith balls that are 13.0 cm apart and have equal charges of −24.0 nC?

daser333 [38]

Answer:

The repulsive force is $3.067\times10^{-4}N$ .

Step-by-step explanation:

Consider the provided information.

The coulomb's law to calculate the repulsive force: $F=\frac{kQ_1Q_2}{r^2}$

Where the value of k is 9.00×10⁹ Nm²/C²

Substitute the respective values in the above formula.

$F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{[(13 cm)(\frac{1m}{100cm} )]^2}$

$F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{(0.13 m)^2}$

$F\approx0.0003067N$

$F=3.067\times10^{-4}N$

Hence, the repulsive force is $3.067\times10^{-4}N$ .

8 0

3 years ago

50 points please help :(

Andre45 [30]

$\frac{(y - 1) {}^{2} }{9 } - \frac{( {x - 2)}^{2} }{100} = 1$

$\frac{(y { - 1)}^{2} }{ {3}^{2} } - \frac{ {(x - 2)}^{2} }{ {100}^{2} } = 1$

$( \frac{y - 1}{3} {)}^{2} - ( \frac{x - 2}{10 } {)}^{2} = 1$

7 0

3 years ago

Read 2 more answers